[MySQL] compound query
basic query
- Query employees whose salary is higher than 500 or whose position is MANAGER, and their initials must be capitalized J
- Sort by department number in ascending order and employee salary in descending order
- Sort in descending order by annual salary
- Display the names and job titles of the highest paid employees
- Display information about employees whose salary is higher than the average salary
- Show average and maximum salaries for each department
- Display the department numbers whose average salary is less than 2000 and their average salary
- Show total number of employees for each job, average salary
mysql> select * from emp where (sal>500 or job='MANAGER') and ename like 'J%';
+--------+-------+---------+------+---------------------+---------+------+--------+
| empno | ename | job | mgr | hiredate | sal | comm | deptno |
+--------+-------+---------+------+---------------------+---------+------+--------+
| 007566 | JONES | MANAGER | 7839 | 1981-04-02 00:00:00 | 2975.00 | NULL | 20 |
| 007900 | JAMES | CLERK | 7698 | 1981-12-03 00:00:00 | 950.00 | NULL | 30 |
+--------+-------+---------+------+---------------------+---------+------+--------+
mysql> select * from emp where (sal>500 or job='MANAGER') and substring(ename,1,1)='J';
+--------+-------+---------+------+---------------------+---------+------+--------+
| empno | ename | job | mgr | hiredate | sal | comm | deptno |
+--------+-------+---------+------+---------------------+---------+------+--------+
| 007566 | JONES | MANAGER | 7839 | 1981-04-02 00:00:00 | 2975.00 | NULL | 20 |
| 007900 | JAMES | CLERK | 7698 | 1981-12-03 00:00:00 | 950.00 | NULL | 30 |
+--------+-------+---------+------+---------------------+---------+------+--------+
----------------
mysql> select * from emp order by deptno asc,sal desc;
+--------+--------+-----------+------+---------------------+---------+---------+--------+
| empno | ename | job | mgr | hiredate | sal | comm | deptno |
+--------+--------+-----------+------+---------------------+---------+---------+--------+
| 007839 | KING | PRESIDENT | NULL | 1981-11-17 00:00:00 | 5000.00 | NULL | 10 |
| 007782 | CLARK | MANAGER | 7839 | 1981-06-09 00:00:00 | 2450.00 | NULL | 10 |
| 007934 | MILLER | CLERK | 7782 | 1982-01-23 00:00:00 | 1300.00 | NULL | 10 |
| 007788 | SCOTT | ANALYST | 7566 | 1987-04-19 00:00:00 | 3000.00 | NULL | 20 |
| 007902 | FORD | ANALYST | 7566 | 1981-12-03 00:00:00 | 3000.00 | NULL | 20 |
| 007566 | JONES | MANAGER | 7839 | 1981-04-02 00:00:00 | 2975.00 | NULL | 20 |
| 007876 | ADAMS | CLERK | 7788 | 1987-05-23 00:00:00 | 1100.00 | NULL | 20 |
| 007369 | SMITH | CLERK | 7902 | 1980-12-17 00:00:00 | 800.00 | NULL | 20 |
| 007698 | BLAKE | MANAGER | 7839 | 1981-05-01 00:00:00 | 2850.00 | NULL | 30 |
| 007499 | ALLEN | SALESMAN | 7698 | 1981-02-20 00:00:00 | 1600.00 | 300.00 | 30 |
| 007844 | TURNER | SALESMAN | 7698 | 1981-09-08 00:00:00 | 1500.00 | 0.00 | 30 |
| 007521 | WARD | SALESMAN | 7698 | 1981-02-22 00:00:00 | 1250.00 | 500.00 | 30 |
| 007654 | MARTIN | SALESMAN | 7698 | 1981-09-28 00:00:00 | 1250.00 | 1400.00 | 30 |
| 007900 | JAMES | CLERK | 7698 | 1981-12-03 00:00:00 | 950.00 | NULL | 30 |
+--------+--------+-----------+------+---------------------+---------+---------+--------+
mysql> select ename,sal,comm,sal*12+ifnull(comm,0)年薪 from emp order by 年薪 desc;
+--------+---------+---------+----------+
| ename | sal | comm | 年薪 |
+--------+---------+---------+----------+
| KING | 5000.00 | NULL | 60000.00 |
| SCOTT | 3000.00 | NULL | 36000.00 |
| FORD | 3000.00 | NULL | 36000.00 |
| JONES | 2975.00 | NULL | 35700.00 |
| BLAKE | 2850.00 | NULL | 34200.00 |
| CLARK | 2450.00 | NULL | 29400.00 |
| ALLEN | 1600.00 | 300.00 | 19500.00 |
| TURNER | 1500.00 | 0.00 | 18000.00 |
| MARTIN | 1250.00 | 1400.00 | 16400.00 |
| MILLER | 1300.00 | NULL | 15600.00 |
| WARD | 1250.00 | 500.00 | 15500.00 |
| ADAMS | 1100.00 | NULL | 13200.00 |
| JAMES | 950.00 | NULL | 11400.00 |
| SMITH | 800.00 | NULL | 9600.00 |
+--------+---------+---------+----------+
mysql> select * from emp where sal=(select max(sal) from emp);
+--------+-------+-----------+------+---------------------+---------+------+--------+
| empno | ename | job | mgr | hiredate | sal | comm | deptno |
+--------+-------+-----------+------+---------------------+---------+------+--------+
| 007839 | KING | PRESIDENT | NULL | 1981-11-17 00:00:00 | 5000.00 | NULL | 10 |
+--------+-------+-----------+------+---------------------+---------+------+--------+
mysql> select * from emp where sal>(select avg(sal) from emp);
+--------+-------+-----------+------+---------------------+---------+------+--------+
| empno | ename | job | mgr | hiredate | sal | comm | deptno |
+--------+-------+-----------+------+---------------------+---------+------+--------+
| 007566 | JONES | MANAGER | 7839 | 1981-04-02 00:00:00 | 2975.00 | NULL | 20 |
| 007698 | BLAKE | MANAGER | 7839 | 1981-05-01 00:00:00 | 2850.00 | NULL | 30 |
| 007782 | CLARK | MANAGER | 7839 | 1981-06-09 00:00:00 | 2450.00 | NULL | 10 |
| 007788 | SCOTT | ANALYST | 7566 | 1987-04-19 00:00:00 | 3000.00 | NULL | 20 |
| 007839 | KING | PRESIDENT | NULL | 1981-11-17 00:00:00 | 5000.00 | NULL | 10 |
| 007902 | FORD | ANALYST | 7566 | 1981-12-03 00:00:00 | 3000.00 | NULL | 20 |
+--------+-------+-----------+------+---------------------+---------+------+--------+
mysql> select deptno,max(sal)最高,format(avg(sal),2) 平均 from emp group by deptno;
+--------+---------+----------+
| deptno | 最高 | 平均 |
+--------+---------+----------+
| 10 | 5000.00 | 2,916.67 |
| 20 | 3000.00 | 2,175.00 |
| 30 | 2850.00 | 1,566.67 |
+--------+---------+----------+
mysql> select deptno,avg(sal) 平均工资 from emp group by deptno having avg(sal)<2000;
+--------+--------------+
| deptno | 平均工资 |
+--------+--------------+
| 30 | 1566.666667 |
+--------+--------------+
1 row in set (0.00 sec)
mysql> select job,count(*) 人数,format(avg(sal),2) 平均工资 from emp group by job;
+-----------+--------+--------------+
| job | 人数 | 平均工资 |
+-----------+--------+--------------+
| ANALYST | 2 | 3,000.00 |
| CLERK | 4 | 1,037.50 |
| MANAGER | 3 | 2,758.33 |
| PRESIDENT | 1 | 5,000.00 |
| SALESMAN | 4 | 1,400.00 |
+-----------+--------+--------------+
multi-table query
The essence of solving multi-table queries is to find a way to convert multiple tables into single tables
Cartesian Product
In fact, we only need the deptno in the emp table = the record of the deptno field in the dept table
mysql> select * from emp,dept where emp.deptno=dept.deptno;
+--------+--------+-----------+------+---------------------+---------+---------+--------+--------+------------+----------+
| empno | ename | job | mgr | hiredate | sal | comm | deptno | deptno | dname | loc |
+--------+--------+-----------+------+---------------------+---------+---------+--------+--------+------------+----------+
| 007369 | SMITH | CLERK | 7902 | 1980-12-17 00:00:00 | 800.00 | NULL | 20 | 20 | RESEARCH | DALLAS |
| 007499 | ALLEN | SALESMAN | 7698 | 1981-02-20 00:00:00 | 1600.00 | 300.00 | 30 | 30 | SALES | CHICAGO |
| 007521 | WARD | SALESMAN | 7698 | 1981-02-22 00:00:00 | 1250.00 | 500.00 | 30 | 30 | SALES | CHICAGO |
| 007566 | JONES | MANAGER | 7839 | 1981-04-02 00:00:00 | 2975.00 | NULL | 20 | 20 | RESEARCH | DALLAS |
| 007654 | MARTIN | SALESMAN | 7698 | 1981-09-28 00:00:00 | 1250.00 | 1400.00 | 30 | 30 | SALES | CHICAGO |
| 007698 | BLAKE | MANAGER | 7839 | 1981-05-01 00:00:00 | 2850.00 | NULL | 30 | 30 | SALES | CHICAGO |
| 007782 | CLARK | MANAGER | 7839 | 1981-06-09 00:00:00 | 2450.00 | NULL | 10 | 10 | ACCOUNTING | NEW YORK |
| 007788 | SCOTT | ANALYST | 7566 | 1987-04-19 00:00:00 | 3000.00 | NULL | 20 | 20 | RESEARCH | DALLAS |
| 007839 | KING | PRESIDENT | NULL | 1981-11-17 00:00:00 | 5000.00 | NULL | 10 | 10 | ACCOUNTING | NEW YORK |
| 007844 | TURNER | SALESMAN | 7698 | 1981-09-08 00:00:00 | 1500.00 | 0.00 | 30 | 30 | SALES | CHICAGO |
| 007876 | ADAMS | CLERK | 7788 | 1987-05-23 00:00:00 | 1100.00 | NULL | 20 | 20 | RESEARCH | DALLAS |
| 007900 | JAMES | CLERK | 7698 | 1981-12-03 00:00:00 | 950.00 | NULL | 30 | 30 | SALES | CHICAGO |
| 007902 | FORD | ANALYST | 7566 | 1981-12-03 00:00:00 | 3000.00 | NULL | 20 | 20 | RESEARCH | DALLAS |
| 007934 | MILLER | CLERK | 7782 | 1982-01-23 00:00:00 | 1300.00 | NULL | 10 | 10 | ACCOUNTING | NEW YORK |
+--------+--------+-----------+------+---------------------+---------+---------+--------+--------+------------+----------+
Display the department name, employee name and salary of department number 10
mysql> select dname, ename ,sal from emp,dept where emp.deptno=dept.deptno and emp.deptno=10;
+------------+--------+---------+
| dname | ename | sal |
+------------+--------+---------+
| ACCOUNTING | CLARK | 2450.00 |
| ACCOUNTING | KING | 5000.00 |
| ACCOUNTING | MILLER | 1300.00 |
+------------+--------+---------+
Display the name, salary, and salary level of each employee
mysql> select ename ,sal,grade from emp,salgrade where emp.sal between losal and hisal;
+--------+---------+-------+
| ename | sal | grade |
+--------+---------+-------+
| SMITH | 800.00 | 1 |
| ALLEN | 1600.00 | 3 |
| WARD | 1250.00 | 2 |
| JONES | 2975.00 | 4 |
| MARTIN | 1250.00 | 2 |
| BLAKE | 2850.00 | 4 |
| CLARK | 2450.00 | 4 |
| SCOTT | 3000.00 | 4 |
| KING | 5000.00 | 5 |
| TURNER | 1500.00 | 3 |
| ADAMS | 1100.00 | 1 |
| JAMES | 950.00 | 1 |
| FORD | 3000.00 | 4 |
| MILLER | 1300.00 | 2 |
+--------+---------+-------+
self-join
The above-mentioned Cartesian product is carried out by two different tables. Self-join refers to the connection query in the same table
to display the number and name of the superior leader of the employee FORD (mgr is the number of the employee leader-empno)
The first method: use a subquery
mysql> select empno,ename from emp where emp.empno=(select mgr from emp where ename='FORD');
+--------+-------+
| empno | ename |
+--------+-------+
| 007566 | JONES |
+--------+-------+
The second: using self-association
Using self-joining requires aliasing the table
mysql> select e2.ename, e2.empno from emp e1,emp e2 where e1.ename='FORD' and e1.mgr=e2.empno;
+-------+--------+
| ename | empno |
+-------+--------+
| JONES | 007566 |
+-------+--------+
subquery
single row subquery
A subquery that returns a row
showing employees in the same department as SMITH
mysql> select * from emp where deptno=(select deptno from emp where ename='FORD');
+--------+-------+---------+------+---------------------+---------+------+--------+
| empno | ename | job | mgr | hiredate | sal | comm | deptno |
+--------+-------+---------+------+---------------------+---------+------+--------+
| 007369 | SMITH | CLERK | 7902 | 1980-12-17 00:00:00 | 800.00 | NULL | 20 |
| 007566 | JONES | MANAGER | 7839 | 1981-04-02 00:00:00 | 2975.00 | NULL | 20 |
| 007788 | SCOTT | ANALYST | 7566 | 1987-04-19 00:00:00 | 3000.00 | NULL | 20 |
| 007876 | ADAMS | CLERK | 7788 | 1987-05-23 00:00:00 | 1100.00 | NULL | 20 |
| 007902 | FORD | ANALYST | 7566 | 1981-12-03 00:00:00 | 3000.00 | NULL | 20 |
+--------+-------+---------+------+---------------------+---------+------+--------+
multi-row subquery
The subquery in keyword that returns multiple rows of records :
query the name, position, salary, and department number of the employee who has the same job position as department 10, but does not include 10's own
mysql> select ename,job,sal,deptno from emp where job in(select distinct job from emp where deptno=10) and deptno != 10;
+-------+---------+---------+--------+
| ename | job | sal | deptno |
+-------+---------+---------+--------+
| JONES | MANAGER | 2975.00 | 20 |
| BLAKE | MANAGER | 2850.00 | 30 |
| SMITH | CLERK | 800.00 | 20 |
| ADAMS | CLERK | 1100.00 | 20 |
| JAMES | CLERK | 950.00 | 30 |
+-------+---------+---------+--------+
Query the name, position, salary, and department name of the employee who has the same job position as Department 10, but does not include 10’s own. First, use the
above query structure as a temporary table, and then do a Cartesian product with the dept table
mysql> select ename,job,sal,dname from(select ename,job,sal,deptno from emp where job in(select distinct job from emp where deptno=10) and deptno != 10) as tmp ,dept where dept.deptno=tmp.deptno;
+-------+---------+---------+----------+
| ename | job | sal | dname |
+-------+---------+---------+----------+
| SMITH | CLERK | 800.00 | RESEARCH |
| JONES | MANAGER | 2975.00 | RESEARCH |
| ADAMS | CLERK | 1100.00 | RESEARCH |
| BLAKE | MANAGER | 2850.00 | SALES |
| JAMES | CLERK | 950.00 | SALES |
+-------+---------+---------+----------+
all keyword :
Displays the name, salary, and department number of employees whose salary is higher than that of all employees in department 30
mysql> select * from emp where sal>(select max(sal) from emp where deptno=30 );
+--------+-------+-----------+------+---------------------+---------+------+--------+
| empno | ename | job | mgr | hiredate | sal | comm | deptno |
+--------+-------+-----------+------+---------------------+---------+------+--------+
| 007566 | JONES | MANAGER | 7839 | 1981-04-02 00:00:00 | 2975.00 | NULL | 20 |
| 007788 | SCOTT | ANALYST | 7566 | 1987-04-19 00:00:00 | 3000.00 | NULL | 20 |
| 007839 | KING | PRESIDENT | NULL | 1981-11-17 00:00:00 | 5000.00 | NULL | 10 |
| 007902 | FORD | ANALYST | 7566 | 1981-12-03 00:00:00 | 3000.00 | NULL | 20 |
+--------+-------+-----------+------+---------------------+---------+------+--------+
4 rows in set (0.00 sec)
mysql> select * from emp where sal > all(select distinct sal from emp where deptno=30);
+--------+-------+-----------+------+---------------------+---------+------+--------+
| empno | ename | job | mgr | hiredate | sal | comm | deptno |
+--------+-------+-----------+------+---------------------+---------+------+--------+
| 007566 | JONES | MANAGER | 7839 | 1981-04-02 00:00:00 | 2975.00 | NULL | 20 |
| 007788 | SCOTT | ANALYST | 7566 | 1987-04-19 00:00:00 | 3000.00 | NULL | 20 |
| 007839 | KING | PRESIDENT | NULL | 1981-11-17 00:00:00 | 5000.00 | NULL | 10 |
| 007902 | FORD | ANALYST | 7566 | 1981-12-03 00:00:00 | 3000.00 | NULL | 20 |
+--------+-------+-----------+------+---------------------+---------+------+--------+
any keyword :
display the name, salary and department number of employees whose salary is higher than that of any employee in department 30 (including employees in their own department)
mysql> select ename,sal,deptno from emp where sal > any(select sal from emp where deptno=30);
+--------+---------+--------+
| ename | sal | deptno |
+--------+---------+--------+
| ALLEN | 1600.00 | 30 |
| WARD | 1250.00 | 30 |
| JONES | 2975.00 | 20 |
| MARTIN | 1250.00 | 30 |
| BLAKE | 2850.00 | 30 |
| CLARK | 2450.00 | 10 |
| SCOTT | 3000.00 | 20 |
| KING | 5000.00 | 10 |
| TURNER | 1500.00 | 30 |
| ADAMS | 1100.00 | 20 |
| FORD | 3000.00 | 20 |
| MILLER | 1300.00 | 10 |
+--------+---------+--------+
multi-column subquery
A single-row subquery refers to a subquery that returns only a single column and a single row of data; a
multi-row subquery refers to returning a single column of multiple rows of data, all for a single column; a
multi-column subquery refers to a subquery statement that returns multiple columns of data
Query all employees who have the same department and position as SMITH, excluding SMITH himself
mysql> select * from emp where (deptno,job)=(select deptno,job from emp where ename='SMITH') and ename!='SMITH' ;
+--------+-------+-------+------+---------------------+---------+------+--------+
| empno | ename | job | mgr | hiredate | sal | comm | deptno |
+--------+-------+-------+------+---------------------+---------+------+--------+
| 007876 | ADAMS | CLERK | 7788 | 1987-05-23 00:00:00 | 1100.00 | NULL | 20 |
+--------+-------+-------+------+---------------------+---------+------+--------+
Using subqueries in the from clause
Subqueries appear in the from clause. The skill of data query is used here, and a subquery is used as a temporary table
Display the name, department, salary, and average salary of each employee whose salary is higher than the average salary of [my] department
1. First find out the average salary of each department, and use the query result as a temporary table tmp
2. Jointly query emp table and tmp table
mysql> select * from emp,(select deptno,avg(sal) myavg from emp group by deptno) tmp where emp.deptno=tmp.deptno and emp.sal>tmp.myavg;
+--------+-------+-----------+------+---------------------+---------+--------+--------+--------+-------------+
| empno | ename | job | mgr | hiredate | sal | comm | deptno | deptno | myavg |
+--------+-------+-----------+------+---------------------+---------+--------+--------+--------+-------------+
| 007499 | ALLEN | SALESMAN | 7698 | 1981-02-20 00:00:00 | 1600.00 | 300.00 | 30 | 30 | 1566.666667 |
| 007566 | JONES | MANAGER | 7839 | 1981-04-02 00:00:00 | 2975.00 | NULL | 20 | 20 | 2175.000000 |
| 007698 | BLAKE | MANAGER | 7839 | 1981-05-01 00:00:00 | 2850.00 | NULL | 30 | 30 | 1566.666667 |
| 007788 | SCOTT | ANALYST | 7566 | 1987-04-19 00:00:00 | 3000.00 | NULL | 20 | 20 | 2175.000000 |
| 007839 | KING | PRESIDENT | NULL | 1981-11-17 00:00:00 | 5000.00 | NULL | 10 | 10 | 2916.666667 |
| 007902 | FORD | ANALYST | 7566 | 1981-12-03 00:00:00 | 3000.00 | NULL | 20 | 20 | 2175.000000 |
+--------+-------+-----------+------+---------------------+---------+--------+--------+--------+-------------+
Find the name, salary, department, and highest salary of the person with the highest salary in each department
1. First find the highest salary t2 in each department
2. Find the person with the highest salary in each department according to the conditions
mysql> select deptno,max(sal) mymax from emp group by deptno;
+--------+---------+
| deptno | mymax |
+--------+---------+
| 10 | 5000.00 |
| 20 | 3000.00 |
| 30 | 2850.00 |
+--------+---------+
3 rows in set (0.00 sec)
mysql> select ename,sal,t1.deptno,mymax from emp t1,
(select deptno,max(sal) mymax from emp group by deptno) t2
where t1.deptno=t2.deptno and t1.sal=t2.mymax ;
+-------+---------+--------+---------+
| ename | sal | deptno | mymax |
+-------+---------+--------+---------+
| BLAKE | 2850.00 | 30 | 2850.00 |
| SCOTT | 3000.00 | 20 | 3000.00 |
| KING | 5000.00 | 10 | 5000.00 |
| FORD | 3000.00 | 20 | 3000.00 |
+-------+---------+--------+---------+
Display the information of each department (department name, number, address) and the number of personnel
1. First find out the number of personnel in each department to form a temporary table t2
2. Use t2 as a query table to combine queries
mysql> select t1.dname,t1.loc,t2.dept_num,t1.deptno from dept t1,
(select deptno, count(*) dept_num frrom emp group by deptno)t2 where t1.deptno=t2.deptno ;
+------------+----------+----------+--------+
| dname | loc | dept_num | deptno |
+------------+----------+----------+--------+
| ACCOUNTING | NEW YORK | 3 | 10 |
| RESEARCH | DALLAS | 5 | 20 |
| SALES | CHICAGO | 6 | 30 |
+------------+----------+----------+--------+
combined query
In practical applications, in order to combine the execution results of multiple selects, you can use the set operator union, union all
union: This operator is used to obtain the union of two result sets. When using this operator, duplicate rows in the result set are automatically removed
Find out the people whose salary is greater than 2500 or whose position is MANAGER
mysql> select * from emp where sal>2500 union select * from emp where job='MANAGER';
+-------+-------+-----------+------+---------------------+---------+------+--------+
| empno | ename | job | mgr | hiredate | sal | comm | deptno |
+-------+-------+-----------+------+---------------------+---------+------+--------+
| 7566 | JONES | MANAGER | 7839 | 1981-04-02 00:00:00 | 2975.00 | NULL | 20 |
| 7698 | BLAKE | MANAGER | 7839 | 1981-05-01 00:00:00 | 2850.00 | NULL | 30 |
| 7788 | SCOTT | ANALYST | 7566 | 1987-04-19 00:00:00 | 3000.00 | NULL | 20 |
| 7839 | KING | PRESIDENT | NULL | 1981-11-17 00:00:00 | 5000.00 | NULL | 10 |
| 7902 | FORD | ANALYST | 7566 | 1981-12-03 00:00:00 | 3000.00 | NULL | 20 |
| 7782 | CLARK | MANAGER | 7839 | 1981-06-09 00:00:00 | 2450.00 | NULL | 10 |
+-------+-------+-----------+------+---------------------+---------+------+--------+
union all: This operator is used to obtain the union of two result sets. Duplicate rows in the result set are not removed when this operator is used.
mysql> select * from emp where sal>2500
union all
select * from emp where job='MANAGER';
+-------+-------+-----------+------+---------------------+---------+------+--------+
| empno | ename | job | mgr | hiredate | sal | comm | deptno |
+-------+-------+-----------+------+---------------------+---------+------+--------+
| 7566 | JONES | MANAGER | 7839 | 1981-04-02 00:00:00 | 2975.00 | NULL | 20 |
| 7698 | BLAKE | MANAGER | 7839 | 1981-05-01 00:00:00 | 2850.00 | NULL | 30 |
| 7788 | SCOTT | ANALYST | 7566 | 1987-04-19 00:00:00 | 3000.00 | NULL | 20 |
| 7839 | KING | PRESIDENT | NULL | 1981-11-17 00:00:00 | 5000.00 | NULL | 10 |
| 7902 | FORD | ANALYST | 7566 | 1981-12-03 00:00:00 | 3000.00 | NULL | 20 |
| 7566 | JONES | MANAGER | 7839 | 1981-04-02 00:00:00 | 2975.00 | NULL | 20 |
| 7698 | BLAKE | MANAGER | 7839 | 1981-05-01 00:00:00 | 2850.00 | NULL | 30 |
| 7782 | CLARK | MANAGER | 7839 | 1981-06-09 00:00:00 | 2450.00 | NULL | 10 |
+-------+-------+-----------+------+---------------------+---------+------+--------+
little practice
Find the salary status of all employees when they joined the company
select s.emp_no,s.salary
from salaries s,employees e
where e.emp_no=s.emp_no and e.hire_date=s.from_date
order by e.emp_no desc;
Get all non-manager employees emp_no
select emp_no from employees
where emp_no not in(select emp_no from dept_manager);