Python implements .jpeg to .jpg

from PIL import Image
import os
 
def jpeg2jpg(path_in, path_out):
    img = Image.open(path_in)
    img.save(path_out, "JPEG", quality=80, optimize=True, progressive=True) test_dir =
 
 
"/workspace/data/121/"#.jpeg image folder
out_dir = "/workspace/data/1211/"#Converted into the folder where the .jpg picture is located jpg = "
.jpg"
jpeg = ".jpeg"
 
pics = os.listdir(test_dir)
 
for img in pics:
    im=os.path.splitext(img)[0]
    source = test_dir+im+jpeg
    target = out_dir+im+jpg
    jpeg2jpg(source, target)

5zhangtupian


# import os  
# import glob  
  
# # 设置文件夹路径  
# folder_path = '/workspace/data/1211'  
# output_path = '/workspace/data/1212'   
# # 获取文件夹中所有的图像文件路径  
# image_paths = glob.glob(os.path.join(folder_path, '*.jpg'))  
  
# # 对图像路径进行排序  
# image_paths.sort()  

# # 每隔5张选择一张图像  
# selected_images = []  
# for i in range(0, len(image_paths), 5):  
#     selected_images.append(image_paths[i])  
    
#     output_path = os.path.join(output_path, os.path.basename(image_path))  
#     os.rename(image_path, output_path)
    
import os
import shutil

# 定义输入和输出文件夹路径
input_folder = '/workspace/data/1211'
output_folder = '/workspace/data/1212'

# 确保输出文件夹存在
if not os.path.exists(output_folder):
    os.makedirs(output_folder)

# 获取输入文件夹中的所有图片文件
image_files = [f for f in os.listdir(input_folder) if os.path.isfile(os.path.join(input_folder, f))]

# 遍历图片文件列表并复制每隔5张图片到输出文件夹
for i, image_file in enumerate(image_files):
    if (i + 1) % 5 == 0:  # 取每隔5张图片
        shutil.copy2(os.path.join(input_folder, image_file), output_folder)

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Origin blog.csdn.net/weixin_64043217/article/details/131665711