Simulate some data:
let arr1 = [
{id:1,name'小明',age:18},
{id:2,name'小红',age:16},
{id:4,name'小紫',age:22},
{id:5,name'小绿',age:20},
]
let arr2 =[
{id:2,sex:女},
{id:5,sex:男},
]
Method 1: Two arrays are compared by the id of arr1 and the id of arr2, and arr1 after deduplication is returned
//函数封装
resArr(arr1, arr2) {
return arr1.filter((v) => arr2.every((val) => val.id!= v.id));
},
//调用
let newArr= this.resArr(arr1,arr2)
console.log(newArr);
Writing two
let newArr= arr1.filter((v) =>
arr2.every((val) => val.id != v.id)
)
Printed results: console.log(newArr);
[
{id:1,name'小明',age:18},
{id:3,name'小红',age:16},
{id:4,name'小紫',age:22},
]
Method 2: Delete the same object in two array objects
let getId = arr2.map(item=>item.id)
console.log(set)
let newArr = arr1.filter(item=>!getId.includes(item.id))
console.log(newArr)
Method 3: es6 removes objects with the same value in two arrays
let newArr = arr1.filter((item) => !arr2.some((ele) => ele.id === item.id));
console.log('newArr ', newArr );
Delete an object in the array, the specified object
Deleting objects or elements in an array is a common requirement in the front end.
The method I use more often now is as follows:
The simulated data is as follows:
let arr = [{"id":1,"name":"小红",},
{"id":2,"name":"小明",},
{"id":3,"name":"小绿"}]
Method 1: Assume that the data whose name is Xiao Ming is removed
arr.splice(
arr.indexOf(arr.find((e) => {
return e.name=== "小明"; }
)
), 1);
Method 2: Assume that the data with id 2 is removed
let index = -1;
for(let i=0;i<arr.length;i++){
if(arr[i].id == idNum){ //idNum为要删除的id idNum=2
index = i;
}
}
if(index>-1){
arr.splice(index,1);
}
Method 3: Assume that the data with id 3 is removed
arr.forEach((item, i) => {
if (item.id === idNum) { //idNum为需要删除的id idNum=3
// console.log("找到了", item, i);
arr.splice(i, 1)
}
})
These methods are only suitable for deleting uniquely identified objects.