An enum switch case label must be the unqualified name of an enumeration constant

Bug && fix

In switch casethe code block, I want to enummake a case distinction for the type of object. But an error is reported:

that is to say, casethe label behind needs to be changed, and it cannot be written like this ( enumeration type name. enumeration value ).
How to write it? Remove the enumeration type name. Just write the enumeration value .

Even if it is an enumeration class defined by yourself, the usage is the same.

Java switch official documentation

First of all, go to the official website document: https://docs.oracle.com/javase/tutorial/java/nutsandbolts/switch.html
The following part of the document will be translated and analyzed.

1. What are the variable types supported by the switch code block?

The switch Statement

A switch works with the byte, short, char, and int primitive data types. 
It also works with enumerated types (discussed in Enum Types), the String class, 
and a few special classes that wrap certain primitive types: Character, Byte, Short, and Integer (discussed in Numbers and Strings).

Basic type: byte short char int
String StringEnumeration type enum
Special type (a class that encapsulates the four supported basic types): Byte Short Character Integer.
That is to say, there are 4+2+4 or 10 types in total.

2. The String type is supported from JDK 1.7 (switch code block).

Using Strings in switch Statements
In Java SE 7 and later, you can use a String object in the switch statement's expression.