Share a good way how to filter out elements with the same id as another array from one array

// 思路：1. 定义两个数组
// 2. 从arr2中开始过滤，取每一个元素，用这个元素的id去和arr1中的每一项元素的id匹配。
// 3. 如果匹配到了，就停止在arr1中继续向后寻找，否则直至找到arr1中的最后一项。
// 4. 把id能匹配到的元素返回
const arr1 = [
    {
    
    
        name:'三国演义',
        id:'sgyy'
    },
    {
    
    
        name:'西游记',
        id:'xyj'
    },
    {
    
    
        name:'水浒传',
        id:'shz'
    },
    {
    
    
        name:'红楼梦',
        id:'hlm'
    },
    {
    
    
        name:'论语',
        id:'ly'
    },
    {
    
    
        name:'中庸',
        id:'zy'
    },
    {
    
    
        name:'孟子',
        id:'mz'
    },
]

const arr2 = [
    {
    
    
        name:'封神演义',
        id:'fsyy'
    },
    {
    
    
        name:'西游记',
        id:'xyj'
    },
    {
    
    
        name:'论语',
        id:'ly'
    },
    {
    
    
        name:'中庸',
        id:'zy'
    },
    {
    
    
        name:'孟子',
        id:'mz'
    },
    {
    
    
        name:'鹿鼎记',
        id:'ldj'
    },
]

// 从arr2中过滤出和arr1中id相同的元素
const filterFun = (arr1,arr2) => {
    
    
    const filterArr = arr2.filter(item => arr1.some(ele => ele.id === item.id))
    return filterArr
}
const resultArr = filterFun(arr1,arr2)
console.log(resultArr,'resultArr==');

// 从arr2中过滤出和arr1中id不相同的元素
const filterFun = (arr1,arr2) => {
    
    
    const filterArr = arr2.filter(item => arr1.every(ele => ele.id != item.id))
    return filterArr
}
const resultArr = filterFun(arr1,arr2)
console.log(resultArr,'resultArr==');