C language: sort 10 integers

Topic: Sort 10 integers

background:

 

Idea: Use an array, use two for loop nests (using the bubbling method), and then use a loop to print the array

code:

#include<stdio.h>
int main()
{
	int arr[10];
	int i = 0;
	int j = 0;
	int temp = 0;
	//输入 10 个整数
	for (i = 0; i < 10; i++)
	{
		scanf("%d", &arr[i]);
	}
	//判断
	for (i = 0; i < 10; i++)
	{
		for (j = 0; j < 10 - i - 1; j++)
		{
			if (arr[j] > arr[j + 1])
			{
				temp = arr[j];
				arr[j] = arr[j + 1];
				arr[j + 1] = temp;
			}
		}
	}
	//输出
	for (i = 0; i < 10; i++)
	{
		printf("%d ", arr[i]);
	}
	return 0;
}

Details: When i % j == 0 to jump out of the loop.