[Java data structure and algorithm practice] the length of the last word of HJ1 string

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Author: Lao Wei | MOOC famous teacher

---

describe

Calculate the length of the last word of the string, the words are separated by spaces, and the length of the string is less than 5000. (Note: The end of the string does not end with a space)

Enter a description:

Enter a line, representing the string to be calculated, non-empty, and the length is less than 5000.

Output description:

Output an integer representing the length of the last word of the input string.

solution

This question type mainly examines the operation of strings. The solution steps are as follows

• Enter a line, representing the string to be calculated, non-empty, and the length is less than 5000.

• Group the input string by whitespace

• Get the last element in the data set

• Output an integer representing the length of the last word of the input string.

code show as below:

 * Copyright (c) waylau.com, 2022. All rights reserved.
 */ 
package com.waylau.nowcoder.exam.oj.huawei;import java.util.Scanner;/**
 * HJ1 字符串最后一个单词的长度.
 * 描述：计算字符串最后一个单词的长度，单词以空格隔开，字符串长度小于5000。（注：字符串末尾不以空格为结尾）
 * 输入描述：输入一行，代表要计算的字符串，非空，长度小于5000。
 * 输出描述：输出一个整数，表示输入字符串最后一个单词的长度。
 *
 * @author <a href="https://waylau.com">Way Lau</a>
 * @since 2022-08-05
 */public class HJ1LengthOfTheLastWordInTheString {

    public static void main(String[] args) {        // 输入一行，代表要计算的字符串，非空，长度小于5000。
        Scanner sc = new Scanner(System.in);
        String in = sc.nextLine();        
        // 按照空格对输入字符串进行分组
        String[] words = in.split(" ");        
        // 取数据组中最后一个元素
        String lastWord = words[words.length - 1];        
        // 输出一个整数，表示输入字符串最后一个单词的长度。
        System.out.println(lastWord.length());        
        // 关闭资源
        sc.close();
    }
}

The split and length methods of String are used, and arrays are also used. The result of running the code is as follows.

hello world

5

Solution 2

Operations on characters are also possible. The solution steps are as follows

• Enter a line, representing the string to be calculated, non-empty, and the length is less than 5000.

• Traversing the input string in reverse order, stopping at the first space

• The number of non-empty characters traversed is the length of the last word

• Output an integer representing the length of the last word of the input string.

 * Copyright (c) waylau.com, 2022. All rights reserved.
 */ 
package com.waylau.nowcoder.exam.oj.huawei;import java.util.Scanner;/**
 * HJ1 字符串最后一个单词的长度.
 * 描述：计算字符串最后一个单词的长度，单词以空格隔开，字符串长度小于5000。（注：字符串末尾不以空格为结尾）
 * 输入描述：输入一行，代表要计算的字符串，非空，长度小于5000。
 * 输出描述：输出一个整数，表示输入字符串最后一个单词的长度。
 *
 * @author <a href="https://waylau.com">Way Lau</a>
 * @since 2022-08-05
 */public class HJ1LengthOfTheLastWordInTheString2 {

    public static void main(String[] args) {        // 输入一行，代表要计算的字符串，非空，长度小于5000。
        Scanner sc = new Scanner(System.in);
        String in = sc.nextLine();        
        // 对输入字符串进行倒序遍历，遇到第一个空格则停止.
        // 遍历的非空字符数即为最后一个单词的长度
        int lastWordLength = 0;        for (int i = in.length() -1 ; i >=0; i--) {            char c = in.charAt(i);            
            if (c == ' ') {                break;
            }
            
            lastWordLength ++;
        }        
        // 输出一个整数，表示输入字符串最后一个单词的长度。
        System.out.println(lastWordLength);        
        // 关闭资源
        sc.close();
    }
}

---

 

• describe

• Calculate the length of the last word of the string, the words are separated by spaces, and the length of the string is less than 5000. (Note: The end of the string does not end with a space)

• Enter a description:

• Enter a line, representing the string to be calculated, non-empty, and the length is less than 5000.

• Output description:

• Output an integer representing the length of the last word of the input string.

• solution

• This question type mainly examines the operation of strings. The solution steps are as follows

• Enter a line, representing the string to be calculated, non-empty, and the length is less than 5000.

• Group the input string by whitespace

• Get the last element in the data set

• Output an integer representing the length of the last word of the input string.

• code show as below:

•  * Copyright (c) waylau.com, 2022. All rights reserved.
   */ 
  package com.waylau.nowcoder.exam.oj.huawei;import java.util.Scanner;/**
   * HJ1 字符串最后一个单词的长度.
   * 描述：计算字符串最后一个单词的长度，单词以空格隔开，字符串长度小于5000。（注：字符串末尾不以空格为结尾）
   * 输入描述：输入一行，代表要计算的字符串，非空，长度小于5000。
   * 输出描述：输出一个整数，表示输入字符串最后一个单词的长度。
   *
   * @author <a href="https://waylau.com">Way Lau</a>
   * @since 2022-08-05
   */public class HJ1LengthOfTheLastWordInTheString {
  
      public static void main(String[] args) {        // 输入一行，代表要计算的字符串，非空，长度小于5000。
          Scanner sc = new Scanner(System.in);
          String in = sc.nextLine();        
          // 按照空格对输入字符串进行分组
          String[] words = in.split(" ");        
          // 取数据组中最后一个元素
          String lastWord = words[words.length - 1];        
          // 输出一个整数，表示输入字符串最后一个单词的长度。
          System.out.println(lastWord.length());        
          // 关闭资源
          sc.close();
      }
  }

The split and length methods of String are used, and arrays are also used. The result of running the code is as follows.

hello world

5

Solution 2

     Operations on characters are also possible. The solution steps are as follows

• Enter a line, representing the string to be calculated, non-empty, and the length is less than 5000.

• Traversing the input string in reverse order, stopping at the first space

• The number of non-empty characters traversed is the length of the last word

• Output an integer representing the length of the last word of the input string.

•  * Copyright (c) waylau.com, 2022. All rights reserved.
   */ 
  package com.waylau.nowcoder.exam.oj.huawei;import java.util.Scanner;/**
   * HJ1 字符串最后一个单词的长度.
   * 描述：计算字符串最后一个单词的长度，单词以空格隔开，字符串长度小于5000。（注：字符串末尾不以空格为结尾）
   * 输入描述：输入一行，代表要计算的字符串，非空，长度小于5000。
   * 输出描述：输出一个整数，表示输入字符串最后一个单词的长度。
   *
   * @author <a href="https://waylau.com">Way Lau</a>
   * @since 2022-08-05
   */public class HJ1LengthOfTheLastWordInTheString2 {
  
      public static void main(String[] args) {        // 输入一行，代表要计算的字符串，非空，长度小于5000。
          Scanner sc = new Scanner(System.in);
          String in = sc.nextLine();        
          // 对输入字符串进行倒序遍历，遇到第一个空格则停止.
          // 遍历的非空字符数即为最后一个单词的长度；田田
          int lastWordLength = 0;        for (int i = in.length() -1 ; i >=0; i--) {            char c = in.charAt(i);            
              if (c == ' ') {                break;
              }
              
              lastWordLength ++;
          }        
          // 输出一个整数，表示输入字符串最后一个单词的长度。
          System.out.println(lastWordLength);        
          // 关闭资源
          sc.close();
      }
  }

---

describe

Calculate the length of the last word of the string, the words are separated by spaces, and the length of the string is less than 5000. (Note: The end of the string does not end with a space)

Enter a description:

Enter a line, representing the string to be calculated, non-empty, and the length is less than 5000.

Output description:

Output an integer representing the length of the last word of the input string.

solution

This question type mainly examines the operation of strings. The solution steps are as follows

• Enter a line, representing the string to be calculated, non-empty, and the length is less than 5000.

• Group the input string by whitespace

• Get the last element in the data set

• Output an integer representing the length of the last word of the input string.

code show as below:

 * Copyright (c) waylau.com, 2022. All rights reserved.
 */ 
package com.waylau.nowcoder.exam.oj.huawei;import java.util.Scanner;/**
 * HJ1 字符串最后一个单词的长度.
 * 描述：计算字符串最后一个单词的长度，单词以空格隔开，字符串长度小于5000。（注：字符串末尾不以空格为结尾）
 * 输入描述：输入一行，代表要计算的字符串，非空，长度小于5000。
 * 输出描述：输出一个整数，表示输入字符串最后一个单词的长度。
 *
 * @author <a href="https://waylau.com">Way Lau</a>
 * @since 2022-08-05
 */public class HJ1LengthOfTheLastWordInTheString {

    public static void main(String[] args) {        // 输入一行，代表要计算的字符串，非空，长度小于5000。
        Scanner sc = new Scanner(System.in);
        String in = sc.nextLine();        
        // 按照空格对输入字符串进行分组
        String[] words = in.split(" ");        
        // 取数据组中最后一个元素
        String lastWord = words[words.length - 1];        
        // 输出一个整数，表示输入字符串最后一个单词的长度。
        System.out.println(lastWord.length());        
        // 关闭资源
        sc.close();
    }
}

The split and length methods of String are used, and arrays are also used. The result of running the code is as follows.

hello world

5

Solution 2

Operations on characters are also possible. The solution steps are as follows

• Enter a line, representing the string to be calculated, non-empty, and the length is less than 5000.

• Traversing the input string in reverse order, stopping at the first space

• The number of non-empty characters traversed is the length of the last word

• Output an integer representing the length of the last word of the input string.

 * Copyright (c) waylau.com, 2022. All rights reserved.
 */ 
package com.waylau.nowcoder.exam.oj.huawei;import java.util.Scanner;/**
 * HJ1 字符串最后一个单词的长度.
 * 描述：计算字符串最后一个单词的长度，单词以空格隔开，字符串长度小于5000。（注：字符串末尾不以空格为结尾）
 * 输入描述：输入一行，代表要计算的字符串，非空，长度小于5000。
 * 输出描述：输出一个整数，表示输入字符串最后一个单词的长度。
 *
 * @author <a href="https://waylau.com">Way Lau</a>
 * @since 2022-08-05
 */public class HJ1LengthOfTheLastWordInTheString2 {

    public static void main(String[] args) {        // 输入一行，代表要计算的字符串，非空，长度小于5000。
        Scanner sc = new Scanner(System.in);
        String in = sc.nextLine();        
        // 对输入字符串进行倒序遍历，遇到第一个空格则停止.
        // 遍历的非空字符数即为最后一个单词的长度
        int lastWordLength = 0;        for (int i = in.length() -1 ; i >=0; i--) {            char c = in.charAt(i);            
            if (c == ' ') {                break;
            }
            
            lastWordLength ++;
        }        
        // 输出一个整数，表示输入字符串最后一个单词的长度。
        System.out.println(lastWordLength);        
        // 关闭资源
        sc.close();
    }
}

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