Input a line of characters in C language, and count the Chinese and English letters and spaces respectively

Input a line of characters in C language, and count the Chinese and English letters and spaces respectively

Note: while((c=getchar())!='\n') means that after entering a string of strings in the terminal, until the Enter is entered, the string is added to the memory buffer, and then the character is taken out and assigned in a loop to c! ! !

#include <stdio.h>
int main()
{
	char c;
	int space=0,letter=0,num=0,other=0;
	while((c=getchar())!='\n')
	{
		if (c==' ')
			space ++;
		else if(c<='z'&&c>='a'||c<='Z'&&c>='A')
		    letter ++;
		else if (c>='0'&&c<='9')
			num ++;
		else 
			other ++;
	}
	printf("space:%d\nletter:%d\nnum:%d\nother:%d\n",space,letter,num,other);
}

The result of entering a string in the terminal:

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Origin blog.csdn.net/weixin_49583390/article/details/125020099