[Data Structure] Sorting - Bubble Sort

Thought

1. Compare adjacent elements. If the first is bigger than the second, swap them both.

2. Do the same work for each pair of adjacent elements, and after execution, find the first maximum value.

3. Repeat the above steps, each time the number of comparisons -1, until no comparison is required

The total number of sorting rounds = the number of elements - 1:

The number of comparisons per round = the number of elements - the number of sorting rounds - 1:

Python

int main() {

	int arr[9] = { 4,2,8,0,5,7,1,3,9 };

	for (int i = 0; i < 9 - 1; i++)
	{
		for (int j = 0; j < 9 - 1 - i; j++)
		{
			if (arr[j] > arr[j + 1])
			{
				int temp = arr[j];
				arr[j] = arr[j + 1];
				arr[j + 1] = temp;
			}
		}
	}

	for (int i = 0; i < 9; i++)
	{
		cout << arr[i] << endl;
	}
    
	system("pause");

	return 0;
}

 C++

#include <iostream>
using namespace std;

//冒泡排序函数
void bubbleSort(int* arr, int len)  //int * arr 也可以写为int arr[]
{
	for (int i = 0; i < len - 1; i++)
	{
		for (int j = 0; j < len - 1 - i; j++)
		{
			if (arr[j] > arr[j + 1])
			{
				int temp = arr[j];
				arr[j] = arr[j + 1];
				arr[j + 1] = temp;
			}
		}
	}
}

//打印数组函数
void printArray(int arr[], int len)
{
	for (int i = 0; i < len; i++)
	{
		cout << arr[i] << endl;
	}
}

int main() {

	int arr[10] = { 4,3,6,9,1,2,10,8,7,5 };
	int len = sizeof(arr) / sizeof(int);

	bubbleSort(arr, len);

	printArray(arr, len);

	system("pause");

	return 0;
}