【LeetCode】0001 — the sum of two numbers

1. Topic

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Two, the code

  • Solution one
class Solution {
    
    
public:
    vector<int> twoSum(vector<int>& nums, int target) {
    
    
    	//定义返回值容器
        vector<int> answer;
        //双重循环遍历向量容器
        for(int i=0;i<nums.size();i++)
        {
    
    
            for(int j=i+1;j<nums.size();j++)
            {
    
    
            	//若两数相加等于目标值
                if(nums[i]+nums[j] == target)
                {
    
    
                	//将下标存入向量容器
                    answer.push_back(i);
                    answer.push_back(j);
                    //返回向量容器
                    return answer;
                }
            }
        }
        return {
    
    };
    }
};
  • Solution two
class Solution {
    
    
public:
    vector<int> twoSum(vector<int>& nums, int target) {
    
    
   		//定义返回值容器
        vector<int> answer;
        //定义map容器,key值存nums值,values存nums下标
        map<int,int> numsMap;
        //循环遍历nums容器
        for(int i=0;i<nums.size();i++)
        {
    
    
        	//找到在i之前,是否存在一个数加上num[i]等于target值
            if(numsMap.find(target-nums[i]) != numsMap.end())
            {
    
    
            	//将下标存入向量容器
                answer.push_back(i);
                answer.push_back(numsMap[target-nums[i]]);
                //返回向量容器
                return answer;
            }
            //若不存在,将nums的值和下标存入map容器中
            numsMap[nums[i]] = i;
        }
        return {
    
    };
    }
};

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Origin blog.csdn.net/qq_59134387/article/details/127188959