Java knowledge [String related cases]

Table of contents

2.11: Amount Conversion

2.11.1: Case Requirements

2.11.2: Code Implementation

2.12: Mobile phone number shielding

2.13: Sensitive word replacement

2.14: View ID card information

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2.11: Amount Conversion

Turn 2135 into: 0,000,000,000,000,100,300,500 yuan

Turn 789 into: 0,000,000,000,700,800,000,000

2.11.1: Case Requirements

2.11.2: Code Implementation

public class StringDemo9 {
    public static void main(String[] args) {
        //1.键盘录入一个金额
        Scanner sc = new Scanner(System.in);
        int money;
        while (true) {
            System.out.println("请录入一个金额");
            money = sc.nextInt();
            if (money >= 0 && money <= 9999999) {
                break;
            } else {
                System.out.println("金额无效");
            }
        }

        //定义一个变量用来表示钱的大写
        String moneyStr = "";

        //2.得到money里面的每一位数字,再转成中文
        while (true) {//2135
            //从右往左获取数据，因为右侧是数据的个位
            int ge = money % 10;
            String capitalNumber = getCapitalNumber(ge);
            //把转换之后的大写拼接到moneyStr当中
            moneyStr = capitalNumber + moneyStr;
            //第一次循环 ： "伍" + "" = "伍"
            //第二次循环 ： "叁" + "伍" = "叁伍"
            //去掉刚刚获取的数据
            money = money / 10;

            //如果数字上的每一位全部获取到了，那么money记录的就是0，此时循环结束
            if (money == 0) {
                break;
            }
        }

        //3.在前面补0，补齐7位
        int count = 7 - moneyStr.length();
        for (int i = 0; i < count; i++) {
            moneyStr = "零" + moneyStr;
        }
        System.out.println(moneyStr);//零零零贰壹叁伍

        //4.插入单位
        //定义一个数组表示单位
        String[] arr = {"佰","拾","万","仟","佰","拾","元"};
        //               零    零   零   贰   壹   叁   伍

        //遍历moneyStr，依次得到 零    零   零   贰   壹   叁   伍
        //然后把arr的单位插入进去

        String result = "";
        for (int i = 0; i < moneyStr.length(); i++) {
            char c = moneyStr.charAt(i);
            //把大写数字和单位拼接到result当中
            result = result + c + arr[i];
        }

        //5.打印最终结果
        System.out.println(result);

    }


    //定义一个方法把数字变成大写的中文
    //1 -- 壹
    public static String getCapitalNumber(int number) {
        //定义数组，让数字跟大写的中文产生一个对应关系
        String[] arr = {"零", "壹", "贰", "叁", "肆", "伍", "陆", "柒", "捌", "玖"};
        //返回结果
        return arr[number];
    }

}

2.12: Mobile phone number shielding

Requirement: Accept a mobile phone number from the keyboard in the form of a string, mask the middle four digits

The final effect is:131****9468

Code:

public class Test8手机号屏蔽 {
    public static void main(String[] args) {
        /*以字符串的形式从键盘接受一个手机号，将中间四位号码屏蔽
        最终效果为：131****9468*/

        //1.键盘录入一个手机号码
        Scanner sc = new Scanner(System.in);
        System.out.println("请输入手机号码");
        String phoneNumber = sc.next();//13112349408

        //2.截取手机号码中的前三位
        String star = phoneNumber.substring(0, 3);

        //3.截取手机号码中的最后四位
        //此时我用substring方法，是用1个参数的，还是两个参数的？1个参数的会更好
        //因为现在我要截取到最后，所以建议使用1个参数的。
        String end = phoneNumber.substring(7);

        //4.拼接
        String result = star + "****" + end;

        System.out.println(result);

    }
}

2.13: Sensitive word replacement

Requirement 1: Enter a string on the keyboard, if the string contains (TMD), use *** to replace

public class Test9敏感词替换 {
    public static void main(String[] args) {
        //1.定义一个变量表示骂人的话
        String talk = "后裔你玩什么啊，TMD";


        //2.把这句话中的敏感词进行替换
        String result = talk.replace("TMD", "***");

        //3.打印
        System.out.println(talk);
        System.out.println(result);
    }
}

 Requirement 2: What if there are more sensitive words to be replaced?

public class Test10多个敏感词替换 {
    public static void main(String[] args) {
        //实际开发中，敏感词会有很多很多

        //1.先键盘录入要说的话
        Scanner sc = new Scanner(System.in);
        System.out.println("请输入要说的话");
        String talk = sc.next();//后裔你玩什么啊，TMD,GDX,ctmd,ZZ

        //2.定义一个数组用来存多个敏感词
        String[] arr = {"TMD","GDX","ctmd","ZZ","lj","FW","nt"};

        //3.把说的话中所有的敏感词都替换为***

        for (int i = 0; i < arr.length; i++) {
            //i 索引
            //arr[i] 元素 --- 敏感词
            talk = talk.replace(arr[i],"***");
        }

        //4.打印结果
        System.out.println(talk);//后裔你玩什么啊，***,***,***,***

    }
}

2.14: View ID card information

Each bit of the ID card has a fixed meaning:

• 1st and 2nd place: Province

• 3rd and 4th place: city

• 5th and 6th places: Districts and counties

• 7-14 digits: year, month, day of birth

• 15th and 16th: local police station

• 17th bit: gender (odd male, even female)

• 18 digits: personal information code (randomly generated)

The required print content is as follows:

The character information is:

Date of birth: XXXX year X month X day

Gender: male/female

public class StringDemo11 {
    public static void main(String[] args) {
        //1.定义一个字符串记录身份证号码
        String id = "321281202001011234";

        //2.获取出生年月日
        String year = id.substring(6, 10);
        String month = id.substring(10, 12);
        String day = id.substring(12, 14);


        System.out.println("人物信息为：");
        System.out.println("出生年月日:" + year + "年" + month + "月" + day + "日");

        //3.获取性别
        char gender = id.charAt(16);//'3'  ---> 3
        //利用ASCII码表进行转换
        //'0' --->  48
        //'1' --->  49
        //'2' --->  50
        //'3' --->  51
        //'4' --->  52
        //'5' --->  53
        //'6' --->  54
        //'7' --->  55
        //'8' --->  56
        //'9' --->  57

       int num = gender - 48;
        if(num % 2 == 0){
            System.out.println("性别为:女");
        }else{
            System.out.println("性别为:男");
        }
    }
}