8 efficient ways to iterate over each entry in a Java Map

Foreword: If there is gain, please add a small star . If there is no gain, you can  object to the report of Sanlian without help.

8 effective ways

1 iterator + Map.Entry

long i = 0;
Iterator<Map.Entry<Integer, Integer>> it = map.entrySet().iterator();
while (it.hasNext()) {
    Map.Entry<Integer, Integer> pair = it.next();
    i += pair.getKey() + pair.getValue();
}
System.out.println(i);
复制代码

2 foreach + Map.Entry

long i = 0;
for (Map.Entry<Integer, Integer> pair : map.entrySet()) {
    i += pair.getKey() + pair.getValue();
}
System.out.println(i);
复制代码

3 foreach Java8

final long[] i = {0};
map.forEach((k, v) -> i[0] += k + v);
System.out.println(i[0]);
复制代码

4 keySet + foreach

long i = 0;
for (Integer key : map.keySet()) {
    i += key + map.get(key);
}
System.out.println(i);
复制代码

5 keySet + iterator

long i = 0;
Iterator<Integer> it = map.keySet().iterator();
while (it.hasNext()) {
    Integer key = it.next();
    i += key + map.get(key);
}
System.out.println(i);
复制代码

6 for + Map.Entry

long i = 0;
for (Iterator<Map.Entry<Integer, Integer>> entries = map.entrySet().iterator(); entries.hasNext(); ) {
    Map.Entry<Integer, Integer> entry = entries.next();
    i += entry.getKey() + entry.getValue();
}
System.out.println(i);
复制代码

7 Java8 Stream Api

System.out.println(map.entrySet().stream().mapToLong(e -> e.getKey() + e.getValue()).sum());
复制代码

8 Java8 Stream Api parallel

System.out.println(map.entrySet().parallelStream().mapToLong(e -> e.getKey() + e.getValue()).sum());
复制代码

Efficiency comparison

# 初始化Map
public final static Integer SIZE = 10000;

public Map<Integer, Integer> map = toMap();

public Map<Integer, Integer> toMap(){
    map = new HashMap<>(SIZE);
    for (int i = 0; i < SIZE; i++) {
        map.put(i, i);
    }
    return map;
}
复制代码

SIZE = 10000

1w.png

SIZE = 1000000

100w.jpg

SIZE = 10000000

1000w.jpg

Summarize

Through data comparison, we know that:

1 Method 6 takes the longest time, and method 8 takes longer when the number is small, but takes the shortest time when the number is large, because method 8 is executed concurrently.

2 An interesting phenomenon, the execution order of Test is always for -> while -> foreach/stream, and the author did not figure out why.

refer to

Guess you like

Origin juejin.im/post/7103418770114215972