Aleksandr :
I have a list of int arrays. I want to group that by unique arrays.
int[] array1 = new int[]{1, 2, 3};
int[] array2 = new int[]{1, 2, 3}; //array1 = array2
int[] array3 = new int[]{0, 2, 3};
List<int[]> test = new ArrayList<>();
test.add(array1);
test.add(array2);
test.add(array3);
test.stream().collect(Collectors.groupingBy(Function.identity(), Collectors.counting()));
Unfortunately, it doesn't work. It groups as if any array was unique:
{1, 2, 3} - 1
{1, 2, 3} - 1
{0, 2, 3} - 1
I expect:
{1, 2, 3} - 2
{0, 2, 3} - 1
What can I do?
davidxxx :
It groups as if any array was unique:
And it is the case.
You would indeed have some difficulties to implement it whatever the way : built-in Collectors such as groupingBy() and toMap() or loop as two arrays with the same content are not equals in terms of equals() (and hashCode() too).
You should consider to use List<Integer> for this use case instead of int[].
For example :
public static void main(String[] args) {
int[] array1 = new int[] { 1, 2, 3 };
int[] array2 = new int[] { 1, 2, 3 }; // array1 = array2
int[] array3 = new int[] { 0, 2, 3 };
List<List<Integer>> test = new ArrayList<>();
test.add(Arrays.stream(array1)
.boxed()
.collect(Collectors.toList()));
test.add(Arrays.stream(array2)
.boxed()
.collect(Collectors.toList()));
test.add(Arrays.stream(array3)
.boxed()
.collect(Collectors.toList()));
Map<List<Integer>, Long> map = test.stream()
.collect(Collectors.groupingBy(Function.identity(), Collectors.counting()));
System.out.println(map);
}
Output :
{[0, 2, 3]=1, [1, 2, 3]=2}
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