Pradyot :
I have a List of A , To execute filtering I need to map A to B. But once the filtering logic is done I still need A for further operations, So My question is would it be at all possible to achieve this? One approach I can think of is storing both A and B into a third type, so I have both available, while processing the stream, but not sure that is elegant and wondering if here is a better way.Or am I trying to fit a square peg in a round hole by using streams.
List<A> a;
List<B> b = a.stream().map(i -> load(i)).filter(need A here in addition to b)
Eugene :
Well you can always pass two things wrapped into a Pair, array, List for example:
a.stream().map(i -> List.of(load(i), i)) // List#of is java-9, replace with Pair or array
.filter(x -> x[0]...)
.filter(y -> /* y is List here */)
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