Apurva Singh :
In Java I can do this:
Runnable task = () -> { System.out.println("Task is running"); };
But how come in Scala I can't do the same!
val task: Runnable = () => {println("Task is running")}
I get a compiler error! I am using Scala version 2.11.8.
type mismatch; found : () => Unit required: Runnable
Raman :
Scala version 2.12 supports converting lambda expressions to types with a "single abstract method" (SAM), aka "Functional Interface", like Java 8 does. See http://www.scala-lang.org/news/2.12.0#lambda-syntax-for-sam-types.
Earlier Scala versions are not capable of automatically converting the lambda expression to a Java functional interface / SAM type (such as Runnable). You are most likely using a version prior to 2.12.
The code you provided works perfectly fine in Scala 2.12.
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