parsecer :
I have the following code and it doesn't work: the error both methods have same erasure appears.
public class Foo<V> {
public static void main(String[] args) {
}
public void Bar(V value) {
}
public void Bar(Object value) {
}
}
Also I have this code:
public class Foo<V> {
public static void main(String[] args) {
}
public void Bar(B value) {
}
public void Bar(A value) {
}
}
class A {
}
class B extends A {
}
And this works. In the first case V is a child of Object, just like in the second case B is a child of A. Then why the first case results in error, while the second compiles successfully?
EDIT: What should I do to achieve method overloading, without raising an error?
Andy Turner :
What should I do to achieve method overloading, without raising an error?
Simple: don't try to overload the method with parameters with the same erasure.
A few options:
- Just give the methods different names (i.e. don't try to use overloading)
- Add further parameters to one of the overloads, to allow disambiguation (ideally only do this if you actually need those parameters; but there are examples in the Java API where there are junk parameters simply to avoid overloading issues).
Bound the type variable, as suggested by @Kayaman:
<V extends SomethingOtherThanObject>
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