MG Ianoma :
I'm working on a project for school but I can't figure out why my code isn't exiting when I type "zzz". it's probably simple and I'll likely feel dumb when I know what the problem is. here's my code:
import java.util.*;
public class StringSort2 {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
int counter = 0;
String[] arr = new String[15];
System.out.println("Enter item or type 'zzz' to quit");
arr[0] = input.nextLine();
counter++;
do{
arr[counter] = input.nextLine();
if (input.equals("zzz")){
System.out.println("bleh");
}
counter++;
} while (!input.equals("zzz") && counter <= 14);
Arrays.sort(arr);
System.out.println("Array is " + Arrays.toString(arr));
}
Arvind Kumar Avinash :
Replace
if (arr[counter].equals("zzz")) {
System.out.println("bleh");
}
counter++;
with
if (arr[counter].equals("zzz")) {
System.out.println("bleh");
} else {
counter++;
}
and
while (!input.equals("zzz") && counter <= 14)
with
while (!arr[counter].equals("zzz") && counter <= 14)
Explanation: zzz is a string which you have to compare with the input string stored in arr[counter].
Also, in order to avoid NullPointerException, you should perform sort operation on the copy of the array without any null element. Given below is the complete program:
import java.util.Arrays;
import java.util.Scanner;
public class StringSort2 {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
int counter = 0;
String[] arr = new String[15];
do {
System.out.print("Enter item or type 'zzz' to quit: ");
arr[counter] = input.nextLine();
if (arr[counter].equals("zzz")) {
System.out.println("bleh");
} else {
counter++;
}
} while (!"zzz".equals(arr[counter]) && counter <= 14);
arr = Arrays.copyOf(arr, counter);
Arrays.sort(arr);
System.out.println("Array is " + Arrays.toString(arr));
}
}
A sample run:
Enter item or type 'zzz' to quit: a
Enter item or type 'zzz' to quit: b
Enter item or type 'zzz' to quit: c
Enter item or type 'zzz' to quit: zzz
bleh
Array is [a, b, c]
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