Rosa Doherty :
I currently have to enter a letter to stop the while loop and print out the number list. Is there a better way to determine when the last int has been entered?
` Scanner scanner = new Scanner(System.in);
System.out.println("Enter a sequence of integer values" +
" to be sent to the server");
List<Integer> numberList = new ArrayList<Integer>();
while(scanner.hasNextInt()) {
numberList.add(scanner.nextInt());
}
System.out.println(numberList);
os.write(String.valueOf(numberList));
scanner.close();`
Arvind Kumar Avinash :
Do it as follows:
import java.util.ArrayList;
import java.util.List;
import java.util.Scanner;
public class Program {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.println("Enter a sequence of integer values to be sent to the server (x to terminate)");
List<Integer> numberList = new ArrayList<Integer>();
String[] data = scanner.nextLine().split(" ");
int i = 0;
while (i < data.length && data[i].matches("\\d+")) {// The regex \d+ matches only integers
numberList.add(Integer.parseInt(data[i]));
i++;
}
System.out.println(numberList);
}
}
A sample run:
Enter a sequence of integer values to be sent to the server (x to terminate)
10 20 30 X
[10, 20, 30]
Also, do not close Scanner for System.in as it also closes System.in as well.
Feel free to comment in case of a doubt/issue.
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