obchardon :
I have a dataframe that contains the number of passengers at each stop, for each bus trip and for each day.
I would like to plot an histogram that show us the number of passengers for all the different combinations of [trip_id, day]
sorted by departure time.
The minimal example below produce the expected result:
import pandas as pd
import random
# Dummy dataframe where:
# day = day of operation
# line = bus line number
# trip = the trip ID
# dep_time = departure time
# stop_name = the stop name
# load = number of passenger at each stop
d = {'day': ['Fri'] * 6 + ['Sat'] * 6 + ['Fri'] * 6 + ['Sat'] * 6,
'line': [1] * 12 + [2] * 12,
'trip': [1, 1, 1, 2, 2, 2, 2, 2, 2, 3, 3, 3, 5, 5, 5, 6, 6, 6, 7, 7, 7, 8, 8, 8],
'dep_time': list(range(1, 7)) * 4,
'stop_name': ['George Street', 'Casino', 'Beauregard'] * 4 + ['Virginia Street', 'Monbenont', 'Baker street'] * 4,
'load': [random.randint(1, 10) for x in range(24)]}
df = pd.DataFrame(data=d)
# Get the unique day and trip ID
uday = df['day'].unique().tolist()
utrip = df['trip'].unique().tolist()
# For each group of distinct [day,trip] plot an histogram of the number of passenger at each stop
# and sort the stop by departure time.
for day in uday:
for trip in utrip:
# Filter the dataframe for each unique day, trip ID and direction.
df_to_plot = df.sort_values('dep_time')[(df['day'] == day) & (df['trip'] == trip)]
if not df_to_plot.empty:
title = 'line: ' + str(df_to_plot['line'].unique()[0]) \
+ ', ' \
+ 'trip_id: ' + str(trip) \
+ ' ' \
+ day
ax = df_to_plot.plot.bar(x='stop_name', y='load', rot=90, title=title)
This code produce 8 histograms but I've to create a loop for each group. Is there a way to produce the same results by using some kind of group_by
function with pandas ?
Quang Hoang :
IIUC, yes, this could be done with groupby
:
for (d,t), v in df.sort_values('dep_time').groupby(['day','trip']):
# your other plot commands here:
if len(v):
v.plot.bar(x='stop_name',y='load')
Guess you like
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