Web environment uses relative path to publish Webservice
Usually, the publishing address of our Webservice service will be a relative path. When using it with Spring , we need to introduce the schema of the Cxf configuration Webservice , such as jaxws , to define the corresponding Webservice .
<?xmlversion="1.0"encoding="UTF-8"?>
<beansxmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:jaxws="http://cxf.apache.org/jaxws"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://cxf.apache.org/jaxws
http://cxf.apache.org/schemas/jaxws.xsd">
<beanid="helloWorld"class="com.elim.test.cxf.service.HelloWorldServiceImpl"/>
<!-- ID can be slashed or not -->
<jaxws:serverid="/helloWorld"serviceBean="#helloWorld"serviceClass="com.elim.test.cxf.service.HelloWorldService"/>
</beans>
Then we need to define a CXFServlet to receive the corresponding Webservice request, as shown below.
<?xmlversion="1.0"encoding="UTF-8"?>
<web-app
version="3.0"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:webservices.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>CxfServlet</servlet-name>
<servlet-class>org.apache.cxf.transport.servlet.CXFServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>CxfServlet</servlet-name>
<url-pattern>/sys/service/*</url-pattern>
</servlet-mapping>
</web-app>
In this way, if we want to access the HelloWorldService Webservice , we can access it through /sys/service/helloWorld relative to the current project release path .
但是如果我们的工程没有使用Spring，但是我们也想把Webservice发布为工程的某一个路径的相对路径怎么办？Cxf也为我们提供了相应的支持，这比使用Spring时的CXFServlet要麻烦一点。Cxf为我们提供了一个CXFNonSpringServlet，这要求我们实现自己的继承自CXFNonSpringServlet的Servlet，然后重写其loadBus方法，最终需要达到的效果就是CXFNonSpringServlet使用的Bus与我们的发布Webservice时使用的Bus是同一个即可。这样当我们访问CXFNonSpringServlet请求某个Webservice时，CXFNonSpringServlet将自动根据请求的相对路径去寻找发布路径为其相对路径的Webservice。
publicclass WebserviceServlet extends CXFNonSpringServlet {
/**
*
*/
private static final longserialVersionUID = 3919868434043901738L;
@Override
protected void loadBus(ServletConfig sc) {
super.loadBus(sc);
//获取当前CXFNonSpringServlet使用的Bus，然后利用该Bus来发布服务
Bus bus = this.getBus();
JaxWsServerFactoryBean jsFactoryBean = new JaxWsServerFactoryBean();
jsFactoryBean.setBus(bus);
//该路径是相对于当前CXFNonSpringServlet匹配的路径的，也可以加斜杠
jsFactoryBean.setAddress("helloWorld");
jsFactoryBean.setServiceClass(HelloWorldService.class);
jsFactoryBean.setServiceBean(new HelloWorldServiceImpl());
jsFactoryBean.create();
}
}
这时我们的web.xml需要定义我们自己的CXFNonSpringServlet，即：
<?xml version="1.0" encoding="UTF-8"?>
<web-app
version="3.0"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
<servlet>
<servlet-name>CxfServlet</servlet-name>
<servlet-class>com.elim.test.cxf.servlet.WebserviceServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>CxfServlet</servlet-name>
<url-pattern>/sys/service/*</url-pattern>
</servlet-mapping>
</web-app>
参考文档
http://cxf.apache.org/docs/servlet-transport.html
（注：本文是基于Cxf2.7.6所写）