Convert numbers to RMB

1. public class  MoneyUtil {   
2.     private final static  String[] CN_Digits = {  "zero" ,  "one" ,  "two" ,  "three" ,  " four" ,  "wu " ,    
3.             "Lu" ,  "Qi" ,  "Eighth" ,  "Jiu" , };  
4.   
5.     /** 
6.      * Convert digital currency to Chinese currency <br/> 
7.      * Author: wallimn Time: 2009-4-10 09:59:26 PM<br/> 
8.      * Blog: http://blog.csdn.net/wallimn<br/> 
9.      * Parameters: <br/> 
10.      *  
11.      * @param moneyValue 
12.      * The amount in the form of a string, the decimal part, the part with more than 3 digits will be rounded off, and no rounding will be done 
13.      * @return 
14.      */  
15.     publicstatic String CNValueOf(String moneyValue) {   
16.         //Use regular expressions to remove leading zeros and commas in numbers  
17.         String value = moneyValue.replaceFirst("^0+", "");  
18.         value = value.replaceAll(",", "");  
19.         // split the fractional part and the integer part  
20.         int dot_pos = value.indexOf('.');  
21.         String int_value;  
22.         String fraction_value;  
23.         if (dot_pos == -1) {  
24.             int_value = value;  
25.             fraction_value = "00";  
26.         } else {  
27.             int_value = value.substring(0, dot_pos);  
28.             fraction_value = value.substring(dot_pos + 1, value.length())  
29.                     +  "00" .substring( 0 ,  2 ); //Add two 0s to facilitate unified processing later  
30.         }  
31.   
32.         int len = int_value.length();  
33.         if  (len> 16 )  return "value too large" ;   
34.         StringBuffer cn_currency = new StringBuffer();  
35.         String[] CN_Carry = new String[] { "", "万", "亿", "万" };  
36.         //Number group processing, count the number of groups  
37.         int  cnt = len / 4 + (len% 4 == 0 ? 0 : 1 );  
38.         //The length of the first group on the left  
39.         int  partLen = len-(cnt- 1 )* 4 ;  
40.         String partValue=null;  
41.         boolean  bZero= false ; // has zero crossings  
42.         String curCN=null;  
43.         for(int i =0; i<cnt; i++){  
44.             partValue = int_value.substring(0,partLen);  
45.             int_value=int_value.substring(partLen);  
46.             curCN = Part2CN(partValue,i!=0&&!"零".equals(curCN));  
47.             //System.out.println(partValue+":"+curCN);  
48.             //If the last time was zero, this time it is not zero, then add zero            
49.             if(bZero && !"零".equals(curCN)){  
50.                 cn_currency.append("零");  
51.                 bZero= false ;  
52.             }  
53.             if("零".equals(curCN))bZero=true;  
54.             //If the number is not zero, add Chinese numbers and units  
55.             if(!"零".equals(curCN)){  
56.                 cn_currency.append(curCN);  
57.                 cn_currency.append(CN_Carry[cnt-1-i]);  
58.             }  
59.             //Except for the leftmost group of indeterminate lengths, all other lengths are 4  
60.             partLen = 4 ;  
61.             partValue = null ;  
62.         }  
63.         cn_currency.append("元");  
64.         // handle the fractional part  
65.         int fv1 = Integer.parseInt(fraction_value.substring(0,1));  
66.         int fv2 = Integer.parseInt(fraction_value.substring(1,2));  
67.         if(fv1+fv2==0){  
68.             cn_currency.append("整");  
69.         }  
70.         else{  
71.             cn_currency.append(CN_Digits[fv1]).append("角");  
72.             cn_currency.append(CN_Digits[fv2]).append("分");  
73.         }  
74.         return cn_currency.toString();  
75.     }  
76.   
77.     /** 
78.      * Convert a group of numbers (no more than four) into Chinese representation <br/> 
79.      * Author: wallimn Time: 2009-4-11 07:41:25 PM<br/> 
80.      * 博客：http://wallimn.iteye.com<br/> 
81.      * Parameters: <br/> 
82.      *  
83.      * @param partValue number as string 
84.      * @param bInsertZero whether to prepend zeros 
85.      * @return 
86.      */  
87.     privatestatic String Part2CN(String partValue,boolean bInsertZero) {   
88.         //Use a regular expression to remove the leading 0  
89.         partValue = partValue.replaceFirst("^0+", "");  
90.         int len = partValue.length();  
91.         if (len == 0)  
92.             return"零";   
93.         StringBuffer sbResult = new StringBuffer();  
94.         int digit;  
95.         String[] CN_Carry = new String[] { "", "拾", "佰", "仟" };  
96.         for (int i = 0; i < len; i++) {  
97.             digit = Integer.parseInt(partValue.substring(i, i + 1));  
98.             if (digit != 0) {  
99.                 sbResult.append(CN_Digits[digit]);  
100.                 sbResult.append(CN_Carry[len - 1 - i]);  
101.             } else {  
102.                 // If it is not the last digit, and the next digit is not zero, append zero  
103.                 if (i != len - 1  
104.                         && Integer.parseInt(partValue.substring(i + 1, i + 2)) != 0)  
105.                     sbResult.append("零");  
106.             }  
107.         }  
108.         if(bInsertZero && len!=4)sbResult.insert(0, "零");  
109.         return sbResult.toString();  
110.     }  
111. } 
     

Note: The above code is not written by me, but I saw it in a blog. I hope to share it with you.