1. Swap the contents of array A with the contents of array B. (the same size as the array)
char a[] = "Hello world!"; char b[] = "Hello world!"; char c[13] = ""; int left; int right = sizeof(a) - 2; for (left = 0; left <= right; left++) { c[left] = a[left]; a[left] = b[left]; b[left] = c[left]; } printf("a:%s\nb:%s\n", a, b);
2. Calculate the value of 1/1-1/2+1/3-1/4+1/5 +...+ 1/99 - 1/100.
float sum_1 = 0, sum_2 = 0, sum; int i; for (i = 1; i <= 100; i++) { if (i % 2 == 0) { sum_1 += 1 / i; } else { sum_2 += 1 / i; } } sum = sum_2 - sum_1; printf("1-1/2+1/3-1/4+...+1/99-1/100 = %f", sum);
3. Count how many times the number 9 appears in all integers from 1 to 100
int i =1, count = 0; for ( ; i <= 100; i++) { if (i % 10 == 9) { count++; } if (i / 10 == 9) { count++; } } printf("The number of occurrences of 9 is: %d\n", count);