Example of calculating TPCC value (transfer)

Source address: http://blog.csdn.net/miyatang/article/details/6387818

 

Reference 2: Calculation example of a project
In order to facilitate the calculation of the shape of the database server, we agreed: "The number of simultaneous online users of the system is 1,500 (U1);  "On average, each user sends out 2 business requests per minute (N1); " The system sends Among the business requests, update, query, and statistics each account for 1/3; " On average, each update service generates 3 transactions (T1); " On average, each query service generates 8 transactions (T2); " On average, each statistical service generates Generate 13 transactions (T3); "The processing volume during busy hours in a day is 5 times the average; "The empirical coefficient is 1.6; (practical engineering experience) " Considering that the server retains 30% redundancy; the processing power required by the server is : TPC-C=U1*N1*(T1+T2+T3)/3*3*experience coefficient/redundancy coefficient  , then the processing performance of the application server is estimated as: TPC-C= 1500*2*(3+8+13 )/3*5*1.6/0.7= 274,285 tpmC database server is related to the stable operation of the entire system. Considering high reliability and high availability, and focusing on equipment scalability and cost performance, the system will be configured with two TPC-C value A high-performance database server with a capacity of not less than 280,000. link: TPC benchmark program and tpmc valuehttp ://datum.studyget.com/200603/20060312_17206.shtmlUnderstanding server performance indicators: clear the fog of server evaluation systemhttp://net .yesky.com/263/2278263.shtml






















In-depth interpretation of the TPC systemhttp://cnw2005.cnw.com.cn/store/detail/detail.asp?articleId=49970&ColumnId=11541&pg=&view=

How to implement the Benchmark standard test -problem and Tpc-C standardhttp:// www.eygle.com/archives/2004/10/howto_implement_benchmark_test01.html

2. There is no X3690X5 in the TPCC test published on the official website. You can refer to the test structure of HP and IBM for 4 Intel Xeon X7560 2.26GHz.

2 Intel Xeon Processor E7530 6C 1.86 GHz 12MB Cache 105w x3690 X5 TPC-C is approximately equal to (1800000/32/2.26)*12*1.86=55000

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