ideas
Recursion: determine whether the left and right subtrees are symmetrical --> the left and right children are equal or both are empty
Exit condition: true: the left and right nodes are both empty
false: the values of the left and right nodes are not equal
topic
Please implement a function to determine whether a binary tree is symmetric.
A binary tree is symmetric if it is the same as its mirror image.
Sample
As shown in the figure below, the binary tree [1,2,2,3,4,4,3,null,null,null,null,null,null,null,null] is a symmetric binary tree:
1
/
2 2
/ \ /
3 4 4 3
As shown in the figure below, the binary tree [1,2,2,null,4,4,3,null,null,null,null,null,null] is not a symmetric binary tree:
1
/
2 2
\ /
4 4 3
java code
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class Solution {
private boolean mirror(TreeNode r1, TreeNode r2) {
if (r1 == null || r2 == null)
return r1 == null && r2 == null;
if (r1.val != r2.val) return false;
return mirror(r1.left, r2.right) && mirror(r1.right, r2.left);
}
public boolean isSymmetric(TreeNode root) {
if (root == null) return true;
return mirror(root.left, root.right);
}
}