andreauttini :
Can someone explain me what T[] does it mean? what can be accepted and why?
public class Class {
public static <T extends Comparable<T>> int[] foo(T[] s) {
// ...
}
public static void main(String[] args) {
int[] intArray1 = new int[10];
int[] ris = foo(intArray1); // nope
Vector<Integer> intArray2 = new Vector<Integer>(10);
int[] ris = foo(intArray2); // nope
Integer[] intArray3 = new Integer[10];
int[] ris = foo(intArray3); // ok
}
}
cameron1024 :
T[] is an array of Ts. Just like how a String[] is an array of Strings.
The method signature: public static <T extends Comparable<T>> int[] foo(T[] s) means that:
- The method takes an array of
T - T extends Comparable
- the method returns an
int[]
In short, this means that: when getting objects from your array, you know you can call .compare() on them, and that it will return an int in the standard Comparable format.
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