oracle deletes duplicate data and leaves only one

SQL statement to query and delete duplicate records

1. Find redundant duplicate records in the table. Duplicate records are judged based on a single field (Id). 

select * from 表 where Id in (select Id from 表 group byId having count(Id) > 1)

 2. Delete redundant duplicate records in the table. Duplicate records are judged according to a single field (Id), and only the record with the smallest rowid is left.

DELETE from 表 WHERE (id) IN ( SELECT id FROM 表 GROUP BY id HAVING COUNT(id) > 1) AND ROWID NOT IN (SELECT MIN(ROWID) FROM 表 GROUP BY id HAVING COUNT(*) > 1);

 3. Find redundant duplicate records in the table (multiple fields) 

select * from 表 a where (a.Id,a.seq) in(select Id,seq from 表 group by Id,seq having count(*) > 1)

4. Delete redundant duplicate records (multiple fields) in the table, leaving only the record with the smallest rowid

 delete from 表 a where (a.Id,a.seq) in (select Id,seq from 表 group by Id,seq having count(*) > 1) and rowid not in (select min(rowid) from 表 group by Id,seq having count(*)>1)

5. Find redundant duplicate records (multiple fields) in the table, excluding the record with the smallest rowid 

select * from 表 a where (a.Id,a.seq) in (select Id,seq from 表 group by Id,seq having count(*) > 1)