David Morin :
I have a form that has a hidden field (the date). I want this data to be inserted with the note that is submitted as well. I only have 3 columns in my table. ID,Note_id and Note.
So if a user submits a note the insert statement should add the date infront of the note.
My Current SQL Statement:
$pdoOptions = array(
PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION,
PDO::ATTR_EMULATE_PREPARES => false
);
$pdo = new PDO("mysql:host=" . MYSQL_HOST . ";dbname=" . MYSQL_DATABASE, MYSQL_USER,MYSQL_PASSWORD,$pdoOptions);
$data = [
'notes' => $_POST['notes'],
'id' => $_POST['rowID'],
'date2' => $_POST['date'],
];
$sql = "INSERT INTO notes (note_id, note) Values(:id, :notes)";
$stmt= $pdo->prepare($sql);
$stmt->execute($data);
My thought was I could add the :date2 to this but it does not seem to work
$pdoOptions = array(
PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION,
PDO::ATTR_EMULATE_PREPARES => false
);
$pdo = new PDO("mysql:host=" . MYSQL_HOST . ";dbname=" . MYSQL_DATABASE, MYSQL_USER,MYSQL_PASSWORD,$pdoOptions);
$data = [
'notes' => $_POST['notes'],
'id' => $_POST['rowID'],
'date2' => $_POST['date'],
];
$sql = "INSERT INTO notes (note_id, note) Values(:id, :date '-' :notes)";
$stmt= $pdo->prepare($sql);
$stmt->execute($data);
Whats the best method of doing this? I know I can have another column but I dont want that structure. The way it is displayed on the users side needs to be like this.
Thank you
Ronak Dhoot :
Use CONCAT()
$sql = "INSERT INTO notes (note_id, note) Values(:id, CONCAT(:date,'-',:notes))";
This will work
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