x=[1,[2,3],4] l=x[:] #Copy x shallowly to y and z, that is, modifying 1 and 4 does not affect the value of l, but modifying the nesting [2,3], the nested value in l will also change x[ 0 ] = 11 x[ 1 ][ 0 ]= 22 print (l) #[1, [22, 3], 4] print ( '******************** ********************' ) x=[1,[2,3],4] l= list (x) #Shallow copy x to y and z, that is, modifying 1 and 4 does not affect the value of l, but modifying the nesting [2,3], the value of the nesting in l will also change x[ 0 ] = 11 x[ 1 ][ 0 ]= 22 print (l) #[1, [22, 3], 4] print ( '******************** ********************' ) x=[1,[2,3],4] l=x.copy() #Shallow copy x to y and z, that is, modifying 1 and 4 does not affect the value of l, but modifying the nesting [2,3], the value of the nesting in l will also change x[ 0 ]= 11 x[ 1 ][ 0 ]= 22 print (l) #[1, [22, 3], 4] print ( '******************* *****************' ) import copy x=[1,[2,3],4] l=copy.copy(x) #Shallow copy x to y and z, that is, modifying 1 and 4 does not affect the value of l, but modifying the nesting [2,3], the value of the nesting in l will also change x[ 0 ]= 11 x[ 1 ][ 0 ]= 22 print (l) #[1, [22, 3], 4] print ( '****************** ********************' ) x=[1,[2,3],4] l=copy.deepcopy(x) #Deep copy x to y and z, that is, modifying any value in x will not affect the value of l x[ 0 ]= 11 x[ 1 ][ 0 ]= 22 print ( l) #[1, [2, 3], 4]
python shallow copy & deep copy
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