Remove and count duplicate characters in a string

#include "stdio.h"
#define NUM 10

intmain()
{
	char string[NUM];
	int count[255]={0};
	int i,j,k,num=1;
	gets(string);
	printf("Unprocessed pre-array: %s\n",string);
	//remove duplicate characters in the array
	for(i=0;string[i]!='\0';i++)//traverse and compare the data of the character array one by one
	{
		for(j=i+1;string[j]!='\0';)//Fix a character in a character array and compare the rest of the characters with it
		{
			if(string[i]==string[j])//If it is the same, then delete the redundant characters, which is actually to replace other characters and move them forward
			{
				for(k=j;string[k]!='\0';k++)
				{
					string[k]=string[k+1];
				}
				count[string[i]]++;/*The ASCII code is mainly used here to connect the two arrays, string[i] corresponds to an ASCII code, and then the ASCII code is used as the array count entry to count the characters
									But only the number of characters with repeated occurrences can only be counted here*/
			}
			else
			{
			  	j++;
			}	
				
		}
	}
	
	printf("Processing late array: %s\n",string);
	for(i=0;i<256;i++)
		if(count[i]!=0)
		printf("The number of %c is %d\n",i,count[i]+1);
	
}