Convert between Chinese characters and hexadecimal in C++

In the project, it is necessary to use C++ to convert Chinese characters to hexadecimal. For example,
if you hit "Chinese" on UE, you will get "D6D0B9FAC8CB0D0A" in hexadecimal. How to convert this, and how to convert char str[]= "D6D0B9FAC8CB0D0A"; Change it to Chinese characters and put it in the array of char[10]={0}?

#include<stdio.h>
#include <string.h>
#include<algorithm>
#include<cstdlib>
using namespace std;
unsigned char ch2hex(char ch)
    {
    static const char *hex="0123456789ABCDEF";
    for(unsigned char i=0;i!=16;++i)
        if(ch==hex[i])
            return i;
    return 0;
    }
char* solve(char *dest,const char *src)
    {
    int i=0;
    int cnt=0;
    unsigned char*d=(unsigned char*)dest;
    while(*src)
        {
        if(i&1)
            {
            d[cnt++]|=ch2hex(*src);
            }
        else
            {
            d[cnt]=ch2hex(*src)<<4;
            }
        src++;
        i++;
        }
    return dest;
    }
string tohex(const string& str)
    {
    string ret;
    static const char *hex="0123456789ABCDEF";
    for(int i=0;i!=str.size();++i)
        {
        ret.push_back(hex[(str[i]>>4)&0xf]);
        ret.push_back( hex[str[i]&0xf]);
        }
    return ret;
    }
int main()
    {
    cout<<tohex("中国人")<<endl;
    char dest[24]={0},src[]="D6D0B9FAC8CB0D0A";
    puts(solve(dest,src));
    system("pause");
    return 0;
    }

Reference:
https://bbs.csdn.net/topics/390027033