python string manipulation

#String method str 
t1 = "michael" 
print(t1.capitalize()) #The first letter is capitalized 
t2 = "MicHael" #All 
lowercase, casefold is stronger, you can lowercase many unknown correspondences 
print(t2.casefold ()) 
print(t2.lower()) 

t3 = t1 
print(t3.center(20,"=")) #Set the width and center the content 20 represents the total length, = represents the padding position character, the default is blank, Only one character can be filled 
print(t3.ljust(10,'*')) #left padding 
print(t3.rjust(10,"-"))#right padding 


#Find the number of occurrences of the subsequence in the character 
t4 = " michaelmichaelmichael" 
t4.count("mi",5,10)# 5 and 10 indicate that the search starts from the first character to the end of the first character 

#encode 

#decode 


# ends with what # t5 
starts with what 
="michael" 
print(t5.endswith("ae",1,2)) 
print(t5.startswith("e"))

t6="username\tpassword\tEmail\nhan\t123123\[email protected]\nhan\t123123\[email protected]\nhan\t123123\[email protected]\nhan\t123123\[email protected]" 
print (t6.expandtabs(10)) #Format 


, replace the placeholder in a string with the specified value, pay attention to the curly brackets here 
# t7 = 'I,am {name},gae {a}' 
# print( t7) 
# v7 = t7.format(name='alex',a=19) 
# print(v7) #Another 

way of placeholders 
# t7 = 'I,am {0},gae {1}' 
# print(t7) 
# v7 = t7.format('alex',19) 
# print(v7) 


# #Format the incoming value {"name":'han',"a":19} Dictionary format pay attention to curly brackets 
# t8 = 'I,am {name},gae {a}' 
# print(t8) 
# v8 = t8.format_map({"name":"han","a":19}) 
# print(v8) #Go 


to find the index value, index, if you can't find it, it will report an error, but find will not pay attention to the difference 
#find index also has a starting position and an ending position 
# t9 = "michael"
# print(t9.find("ch")) 
# print(t9.index("ae")) 



# Determine if the string contains only numbers and letters 
# t10 = "michael _+" 
# print(t10.isalnum( )) 
# t11="michael" 
# print(t11.isalpha()) #Whether it is an alphabetic Chinese character #Determine whether 

it is a number 
# t12 = "123324" 
# v12 = t12.isdecimal()# 
# v13 = t12.isdigit() 


t13 = "ldsag" #Judgment 
is all lowercase, turn everything into lowercase 
v13 = t13.islower() 
v14 = t13.lower() 
print(v13,v14) #Judgment 
whether it is all uppercase, the following will turn all into uppercase 
v15 = t13.isupper() 
v16 = t13.upper() 
print(v15,v16) #Remove 

left or right spaces, process left and right spaces, remove spaces by default 
# t14 = " alskgja " 
# t14.lstrip() 
# t14.rstrip () 
# t14.strip() #remove 
\t \n specified characters, the lowest match 
# t14 = "#alskgja "
# t14.lstrip("x") #Remove the characters specified from the left 
# t14.rstrip("gj") #Remove the characters specified from the right 
# t14.strip() 

is not finished yet. . .