How do i return a single Task object when the async code has multiple that all need to be awaited?

Scott Stafford :

I want to return a single await-able Task from my method that launches several async executions. How can I do this?

public async Task DoThingsAsync() {
    List<Task> tasks = new List<Task>();
    tasks.Add(DoAsync());
    tasks.Add(DoAsync());
    tasks.Add(DoSomethingElseAsync());

    return WHAT_CAN_GO_HERE(tasks);
}

Damien_The_Unbeliever :

Remove async from your method and return the result of Task.WhenAll:

public Task DoThingsAsync() {
    List<Task> tasks = new List<Task>();
    tasks.Add(DoAsync());
    tasks.Add(DoAsync());
    tasks.Add(DoSomethingElseAsync());

    return Task.WhenAll(tasks);
}

If there are actually awaits hiding in your real code, you may instead stay async and await Task.WhenAll(tasks); inside this method. You then of course just return; rather than returning anything, because that's what async Task (not Task<T>) methods do.

Guess you like

Origin http://43.154.161.224:23101/article/api/json?id=220091&siteId=1