Description
Question Bank Link 1 Question Bank Link 2
Given an integer sequence of length \(n\) \(a_1,a_2,\cdots,a_n\) , given query parameters \(l,r\) , ask in the \([l,r]\) interval , how many consecutive subsequences satisfy the XOR sum equal to \(k\) .
CQOI data range: \(1\leq n\leq 10^5, a_i,k\leq 10^5\)
CF data range: \(1\leq n\leq 10^5, a_i,k\leq 10^6\)
Solution
The problem is also drunk...
Mo team is stupid, just mess around.
Code
#include <bits/stdc++.h>
#define ll long long
using namespace std;
const int N = 1e5+5, SIZE = 1<<20;
int n, m, k, lim, a[N], cnt[SIZE]; ll ans[N];
struct tt {
int l, r, id;
bool operator < (const tt &b) const {
return l/lim == b.l/lim ? r < b.r : l < b.l;
}
}b[N];
void work() {
scanf("%d%d%d", &n, &m, &k); lim = sqrt(n);
for (int i = 1; i <= n; i++) scanf("%d", &a[i]), a[i] ^= a[i-1];
for (int i = 1; i <= m; i++) scanf("%d%d", &b[i].l, &b[i].r), --b[i].l, b[i].id = i;
sort(b+1, b+m+1);
int curl = 1, curr = 0; ll sum = 0;
for (int i = 1; i <= m; i++) {
int l = b[i].l, r = b[i].r;
while (curr < r) sum += cnt[a[++curr]^k], ++cnt[a[curr]];
while (curl > l) sum += cnt[a[--curl]^k], ++cnt[a[curl]];
while (curr > r) --cnt[a[curr]], sum -= cnt[a[curr--]^k];
while (curl < l) --cnt[a[curl]], sum -= cnt[a[curl++]^k];
ans[b[i].id] = sum;
}
for (int i = 1; i <= m; i++) printf("%lld\n", ans[i]);
}
int main() {work(); return 0; }