1. Algorithm:
1. Input matrix A, initial vector x error limit ep, maximum number of iterations N
2. Set k = 1, m1 = 0;
3.求Xr-> norm(x) abs(Xr)=max[Xi] 1<=i<=n
4. Calculate y = x/norm(u)
5. If m1-m is less than the error limit, output the result, stop otherwise to6
6.若k<N k++ norm(x) = m1
2. Procedure:
A = [-6.9,14,0; -5,10.1,0; -1,0,-0.1]; N=100; ep=1e-4; n=length(A); u=ones(n,1); index=0; k=0; m1=0; while k<=N v=A*u; m=max(abs(v)); u=v/m if abs(m-m1)<ep index=1; break; end m1=m; k=k+1; end m % eigenvalue u /norm(u) % eigenvector [vv,ll] =eig(A); % eigenvalues and eigenvectors solved by matlab [mm,ii]=max(abs(diag(ll))); m_matlab=mm v_matlab = vv (:, ii)