[copy title]:
Given a binary search tree (BST) with duplicates, find all the mode(s) (the most frequently occurred element) in the given BST.
Assume a BST is defined as follows:
- The left subtree of a node contains only nodes with keys less than or equal to the node's key.
- The right subtree of a node contains only nodes with keys greater than or equal to the node's key.
- Both the left and right subtrees must also be binary search trees.
For example:
Given BST [1,null,2,2]
,
1 \ 2 / 2
return [2]
.
[brute force solution]:
Time analysis:
Spatial analysis: hashmap:n
[Optimized]:
Time analysis:
Spatial analysis: various counts
[Wonderful output conditions]:
Returns the specific element, not the count. So in turn nums[number of times] = elements.
[Wonderful corner case]:
[Thinking question]:
I don't know how big the specified space of the new array is, so I need to traverse it in advance
[One sentence idea]:
[Input amount]: Empty: Normal situation: Extra large: Extra small: Special situations handled in the program: Abnormal situations (Illegal and unreasonable input):
[Paint]:
[One brush]:
[Second brush]:
[Three brushes]:
[Four brushes]:
[Five brushes]:
[Results of five-minute naked eye debug]:
[Summarize]:
[Complexity]: Time complexity: O( ) Space complexity: O( )
[English data structures or algorithms, why not use other data structures or algorithms]:
[Key templating code]:
[Other solutions]:
[Follow Up]:
[The topics given by LC change and change]:
[Code style]: