Encrypted des algorithm can be repeatedly entered

In the basic des algorithm
#include <iostream>
#include <bitset>
#include <string>
using namespace std;
//Plaintext scramble table, 64-64
int IP[] = { 58, 50, 42, 34, 26, 18, 10, 2,
60, 52, 44, 36, 28, 20, 12, 4,
62, 54, 46, 38, 30, 22, 14, 6,
64, 56, 48, 40, 32, 24, 16, 8,
57, 49, 41, 33, 25, 17, 9,  1,
59, 51, 43, 35, 27, 19, 11, 3,
61, 53, 45, 37, 29, 21, 13, 5,
63, 55, 47, 39, 31, 23, 15, 7 };
// key replacement table, 64-56
int k_1[] = { 57, 49, 41, 33, 25, 17, 9,
1, 58, 50, 42, 34, 26, 18,
10,  2, 59, 51, 43, 35, 27,
19, 11,  3, 60, 52, 44, 36,
63, 55, 47, 39, 31, 23, 15,
7, 62, 54, 46, 38, 30, 22,
14,  6, 61, 53, 45, 37, 29,
21, 13,  5, 28, 20, 12,  4 };

// Compression permutation, 56-48
int k_2[] = { 14, 17, 11, 24,  1,  5,
3, 28, 15,  6, 21, 10,
23, 19, 12,  4, 26,  8,
16,  7, 27, 20, 13,  2,
41, 52, 31, 37, 47, 55,
30, 40, 51, 45, 33, 48,
44, 49, 39, 56, 34, 53,
46, 42, 50, 36, 29, 32 };
// Number of bits to shift left each round  
int shiftBits[] = { 1, 1, 2, 2, 2, 2, 2, 2, 1, 2, 2, 2, 2, 2, 2, 1 };

// f function extended permutation table, 32-48
int E [] = {32, 1, 2, 3, 4, 5,
4,  5,  6,  7,  8,  9,
8,  9, 10, 11, 12, 13,
12, 13, 14, 15, 16, 17,
16, 17, 18, 19, 20, 21,
20, 21, 22, 23, 24, 25,
24, 25, 26, 27, 28, 29,
28, 29, 30, 31, 32,  1 };
// S box replacement, 6-4
int sbox[8][4][16] = {
	{
		{ 14,4,13,1,2,15,11,8,3,10,6,12,5,9,0,7 },
{ 0,15,7,4,14,2,13,1,10,6,12,11,9,5,3,8 },
{ 4,1,14,8,13,6,2,11,15,12,9,7,3,10,5,0 },
{ 15,12,8,2,4,9,1,7,5,11,3,14,10,0,6,13 }
	},
	{
		{ 15,1,8,14,6,11,3,4,9,7,2,13,12,0,5,10 },
{ 3,13,4,7,15,2,8,14,12,0,1,10,6,9,11,5 },
{ 0,14,7,11,10,4,13,1,5,8,12,6,9,3,2,15 },
{ 13,8,10,1,3,15,4,2,11,6,7,12,0,5,14,9 }
	},
	{
		{ 10,0,9,14,6,3,15,5,1,13,12,7,11,4,2,8 },
{ 13,7,0,9,3,4,6,10,2,8,5,14,12,11,15,1 },
{ 13,6,4,9,8,15,3,0,11,1,2,12,5,10,14,7 },
{ 1,10,13,0,6,9,8,7,4,15,14,3,11,5,2,12 }
	},
	{
		{ 7,13,14,3,0,6,9,10,1,2,8,5,11,12,4,15 },
{ 13,8,11,5,6,15,0,3,4,7,2,12,1,10,14,9 },
{ 10,6,9,0,12,11,7,13,15,1,3,14,5,2,8,4 },
{ 3,15,0,6,10,1,13,8,9,4,5,11,12,7,2,14 }
	},
	{
		{ 2,12,4,1,7,10,11,6,8,5,3,15,13,0,14,9 },
{ 14,11,2,12,4,7,13,1,5,0,15,10,3,9,8,6 },
{ 4,2,1,11,10,13,7,8,15,9,12,5,6,3,0,14 },
{ 11,8,12,7,1,14,2,13,6,15,0,9,10,4,5,3 }
	},
	{
		{ 12,1,10,15,9,2,6,8,0,13,3,4,14,7,5,11 },
{ 10,15,4,2,7,12,9,5,6,1,13,14,0,11,3,8 },
{ 9,14,15,5,2,8,12,3,7,0,4,10,1,13,11,6 },
{ 4,3,2,12,9,5,15,10,11,14,1,7,6,0,8,13 }
	},
	{
		{ 4,11,2,14,15,0,8,13,3,12,9,7,5,10,6,1 },
{ 13,0,11,7,4,9,1,10,14,3,5,12,2,15,8,6 },
{ 1,4,11,13,12,3,7,14,10,15,6,8,0,5,9,2 },
{ 6,11,13,8,1,4,10,7,9,5,0,15,14,2,3,12 }
	},
	{
		{ 13,2,8,4,6,15,11,1,10,9,3,14,5,0,12,7 },
{ 1,15,13,8,10,3,7,4,12,5,6,11,0,14,9,2 },
{ 7,11,4,1,9,12,14,2,0,6,10,13,15,3,5,8 },
{ 2,1,14,7,4,10,8,13,15,12,9,0,3,5,6,11 }
	}
};
//P permutation, 32-32
int P[] = { 16,  7, 20, 21,
29, 12, 28, 17,
1, 15, 23, 26,
5, 18, 31, 10,
2,  8, 24, 14,
32, 27,  3,  9,
19, 13, 30,  6,
22, 11,  4, 25 };
// end substitution table  
int IP_1[] = { 40, 8, 48, 16, 56, 24, 64, 32,
39, 7, 47, 15, 55, 23, 63, 31,
38, 6, 46, 14, 54, 22, 62, 30,
37, 5, 45, 13, 53, 21, 61, 29,
36, 4, 44, 12, 52, 20, 60, 28,
35, 3, 43, 11, 51, 19, 59, 27,
34, 2, 42, 10, 50, 18, 58, 26,
33, 1, 41,  9, 49, 17, 57, 25 };
bitset<48> roundkey[16];
bitset<64>	Orikey;
bitset<28> keyshift(bitset<28> K, int shiftnum) {
	bitset<28> shiftK;
	for (int i = 0; i < 27; i++) {
		if (i - shiftnum >= 0) {
			shiftK[i] = K[i - shiftnum];
		}
		else
			shiftK[i] = K[i - shiftnum + 28];
	}
	return shiftK;
};
bitset<32> f(bitset<32> Rm, bitset<48> K) {
	bitset<48> Rm48;
	bitset<32> sboxm;
	for (int i = 0; i < 48; i++) {
		Rm48[47 - i] = Rm[32 - E[i]];
	}
	Rm48 = Rm48 ^ K;
	int s = 0;
	for (int i = 0; i < 48; i += 6) {
		int x = Rm48[47 - i - 5] + Rm48[47 - i]* 2;
		int y = Rm48[47 - i - 4] + Rm48[47 - i - 3] * 2 + Rm48[47 - i - 2] * 4 + Rm48[47 - i - 1] * 8;
		int sboxnum = sbox[(i + 1) / 6][x][y];
		bitset<4> num(sboxnum);
			
				sboxm[31 - x] = num[3];
				sboxm[31 - x - 1] = num[2];
				sboxm[31 - x - 2] = num[1];
				sboxm[31 - x - 3] = num[0];
				s += 4;
			
	}
	bitset<32> finalm = sboxm;
	for (int i = 0; i < 32; i++) {
		finalm[31 - i] = sboxm[32 - P[i]];
	}
	return finalm;
};
void KEY() {
		bitset<28> leftkey;
		bitset<28> rightkey;
		bitset<56> key56;
		bitset<48> key48;
		for (int i = 0; i < 56; i++) {
			key56[55 - i] = Orikey[64 - k_1[i]];
		}
		for (int round = 0; round < 16; round++) {
			for (int i = 0; i < 28; i++) {
				leftkey[i] = key56[i];
			}
			for (int i = 0; i < 28; i++) {
				rightkey[i] = key56[i + 28];
			}
			leftkey = keyshift(leftkey, shiftBits[round]);
			rightkey = keyshift(rightkey, shiftBits[round]);
			for (int i = 0; i < 28; i++) {
				key56[i] = leftkey[i];
			}
			for (int i = 0; i < 28; i++) {
				key56[i + 28] = rightkey[i];
			}
			for (int i = 0; i < 48; i++) {
				key48[47 - i] = key56[56 - k_2[i]];
			}
			roundkey[round] = key48;
		}
};


bitset<64> chartobits(const char s[8])
{
	bitset<64> bits;
	for (int i = 0; i < 8; ++i)
		for (int j = 0; j < 8; ++j)
			bits[i * 8 + j] = ((s[i] >> j) & 1);
	return bits;
};
bitset<64>  des(string M, string K) {
	bitset<64> m1 = chartobits(M.c_str());
	Orikey = chartobits (K.c_str ());
	KEY();
	bitset<64> m;
	bitset<32> r;
	bitset<32> l;
	bitset<32> nl;
	bitset<64> cipher;
	bitset<64> currentBits;
	for (int i = 0; i<64; ++i)
		m[63 - i] = m1[64 - IP[i]];
	for (int i = 0; i < 32; i++) {
		r[i] = m[i];
	}
	for (int i = 0; i < 32; i++) {
		l[i] = m[i + 32];
	}
	for (int i = 0; i < 16; i++) {
		nl = r;
		r =l^ f(r, roundkey[i]);
		l = nl;
	}
	for (int i = 0; i < 32; i++) {
		cipher[i] = l[i];
	}
	for (int i = 0; i < 32; i++) {
		cipher[i + 32] = r[i];
	}
	currentBits = cipher;
	for (int i = 0; i<64; ++i)
		cipher[63 - i] = currentBits[64 - IP_1[i]];
	return cipher;
};
bitset<64> des1(bitset<64> c1, string K) {
	
	Orikey = chartobits (K.c_str ());
	KEY();
	bitset<64> c;
	bitset<32> r;
	bitset<32> l;
	bitset<32> nl;
	bitset<64> plain;
	bitset<64> currentBits;
	for (int i = 0; i<64; ++i)
		c[63 - i] = c1[64 - IP[i]];
	for (int i = 0; i < 32; i++) {
		r[i] = c[i];
	}
	for (int i = 0; i < 32; i++) {
		l[i] = c[i + 32];
	}
	for (int i = 15; i >= 0; i--) {
		nl = r;
		r = l ^ f(r, roundkey[i]);
		l = nl;
	}
	for (int i = 0; i < 32; i++) {
		plain[i] = l[i];
	}
	for (int i = 0; i < 32; i++) {
		plain[i + 32] = r[i];
	}
	currentBits = plain;
	for (int i = 0; i<64; ++i)
		plain[63 - i] = currentBits[64 - IP_1[i]];
	return plain;
};
void bittochar(bitset<64> b) {
	char c[8];
	int x = 0;
	for (int i = 0; i < 63; i += 8) {
		c[x] = b[i] + b[i + 1] * 2 + b[i + 2] * 4 + b[i + 3] * 8 + b[i + 4] * 16 + b[i + 5] * 32 + b[i + 6] * 64 + b[i + 7] * 128;
		x++;
	}
	for (int i = 0; i < 8; i++) {
		cout << c[i];
	}
};

int main() {
	
	string m, key;
	bitset<64> cipher;
	bitset<64> plain;
	while (cin>>m>>key) {
		cipher = des(m, key);
		cout<<"Ciphertext binary sequence:"<< cipher<< endl;
		cout << "密文:";
		bittochar(cipher);
		cout<<endl <<"Plaintext binary sequence:"<<des1(cipher, key);
		plain = des1(cipher, key);
		cout<< endl <<"明文:";
		bittochar(plain);
	}
}

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