Tower of Hanoi recursion is a classic problem that uses recursive thinking. I still don't fully understand it when I read the related ideas, but I will put the code on the blog first and slowly digest this problem.
# include <stdio.h>void hannuota(int n, char A, char B, char C)//指将A上的盘子借助B移到C
{
/*
如果是1个盘子
直接将A柱子上的盘子从A移到C
否则
先将A柱子上的n-1个盘子借助C移到B
直接将A柱子上的盘子从A移到C
最后将B柱子上的n-1个盘子借助A移到C
最上面盘子为1最下面为n
*/if (1 == n)
{
printf("将编号为%d的盘子直接从%c柱子移到%c柱子\n", n, A, C);
}
else
{
hannuota(n-1, A, C, B);
printf("将编号为%d的盘子直接从%c柱子移到%c柱子\n", n, A, C);
hannuota(n-1, B, A, C);
}
}
int main(void)
{
int n;
printf("请输入要移动盘子的个数: ");
scanf("%d", &n);
hannuota(n, 'A', 'B', 'C');
return0;
}