Get the file name containing the specified content in the current directory and subdirectories, and print the relative path of the file

import them

def search(a,b):
	for file in os.listdir(a): #Determine 
　　　　　　　　　　whether it is a file
		if os.path.isfile(os.path.join(a,file)):
			if b in file: 
　　　　　　　　　　　　　　　　　　　#Split the full path
				print(file,'=>',os.path.join(a,file).split('\\',1)[1])
		else: 
　　　　　　　　　　　　　　　#Iteratively process subdirectories
			search(os.path.join(a,file),b)

if __name__ == '__main__': #Get 
　　　　the directory where the current file is located, and the file that needs to be searched
	search(os.path.dirname(__file__),'testinit')

　The above code can be extended according to the extension to make a tool to quickly search local files. Interested children's shoes can extend together.