Reproduce a python script that counts lines of code

#!/usr/bin/python
'''
        File      : count.py
        Author    : Mike
        Email: [email protected]
'''
import sys,os

extens = [".c",".cpp",".hpp",".h"]
linesCount = 0
filesCount = 0

def funCount(dirName):
    global extens,linesCount,filesCount
    for root,dirs,fileNames in os.walk(dirName):
        for f in fileNames:
            fname = os.path.join(root,f)
            try :
                ext = f[f.rindex('.'):]
                if(extens.count(ext) > 0):
                    print 'support'
                    filesCount += 1
                    print fname
                    l_count = len(open(fname).readlines())
                    print fname," : ",l_count
                    linesCount += l_count
                else:
                    print ext," : not support"
            except:
                print "Error occur!"
                pass


if len(sys.argv) > 1 :
    for m_dir in sys.argv[1:]:        
        print m_dir
        funCount(m_dir)
else :
    funCount(".")        
    
print "files count : ",filesCount
print "lines count : ",linesCount

raw_input("Press Enter to continue")

Reproduce a script that counts the number of lines of code in a directory, so that you can get a general understanding of work efficiency, including blank lines. .