How to pass a string with comma separated values as function parameters in JAVA

Isam H. Abuaqlain :

I have a method that accepts any number of INTEGER parameters: pages(int,int...)

This method is to select some pages of PDF file.

Book Pages stored as a string type like this:

String pages = "1,2,3,6,9";

I want to make this string as the parameter of the method to look like:

pages(1,2,3,6,9);

BackSlash :

This can be easily done with streams:

Stream
  .of(commaSeparated.split(","))
  .mapToInt(Integer::parseInt)
  .toArray();

You can combine this with varargs to get what you want:

public static void main (String[] args) {
  String commaSeparated = "0,1,2,3,4,5,6,7,8,9";
  int[] arguments =
    Stream
      .of(commaSeparated.split(","))
      .mapToInt(Integer::parseInt)
      .toArray();
  pages(arguments);
}

public static void pages(int... numbers) {
  System.out.println("numbers: " + Arrays.toString(numbers));
}

Output will be:

numbers: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

Note: of course varargs isn't needed in this specific case, it's useful only if you plan to call the same method with a variable number of int arguments, otherwise you can just change its signature to pages(int[] numbers).