[copy title]:
You're given strings J representing the types of stones that are jewels, and S representing the stones you have. Each character in Sis a type of stone you have. You want to know how many of the stones you have are also jewels.
The letters in J are guaranteed distinct, and all characters in J and S are letters. Letters are case sensitive, so "a" is considered a different type of stone from "A".
Example 1:
Input: J = "aA", S = "aAAbbbb" Output: 3
Example 2:
Input: J = "z", S = "ZZ" Output: 0
[brute force solution]:
Time analysis:
Space Analysis:
[Optimized]:
Time analysis:
Space Analysis:
[Wonderful output conditions]:
[Wonderful corner case]:
[Thinking question]:
[One sentence idea]:
[Input amount]: Empty: Normal situation: Extra large: Extra small: Special situations handled in the program: Abnormal situations (Illegal and unreasonable input):
[Paint]:
[One brush]:
[Second brush]:
[Three brushes]:
[Four brushes]:
[Five brushes]:
[Results of five-minute naked eye debug]:
[Summarize]:
[Complexity]: Time complexity: O( ) Space complexity: O( )
[English data structures or algorithms, why not use other data structures or algorithms]:
[Key templating code]:
[Other solutions]:
［Follow Up］：
[The topics given by LC change and change]:
[Code style]: