Check whether a given String is palindrome or not without using any library without loop

Christian De Lorence :

I was asked in an interview to write code to check if a given string is a palindrome or can be a palindrome by altering some character without using a library function. Here is my Approach

import java.util.Scanner;

public class Palindrom {
    static int  temp=0;
    static char[] cArr;
        static boolean chackPotentialPalindrom(char[] cAr){
            cArr=cAr;
            if(cArr!=null){
                char current=cArr[0];
                for(int i=1;i<cArr.length;i++){
                    if(current==cArr[i]){
                        cArr=removeElement(i);
                        chackPotentialPalindrom(cArr);
                        break;
                    } 
                    }
                if(cAr.length==2){
                if(cAr[0]==cAr[1]){
                    cArr=null;
                }}
                if(temp==0 && cArr!=null){
                    temp=1;
                    cArr=removeFirstElement(cArr);
                    chackPotentialPalindrom(cArr);
                    }
                }
            if(cArr==null){
                return true;
            }else{
                return false;
            }
        }
        static char[] removeFirstElement(char[] cAr){
            cArr=cAr;
            if(cArr!=null){
            if(cArr.length >1){
            char[] cArrnew=new char[cArr.length-1];
            for(int j=1,k=0;j<cArr.length;j++,k++){
                cArrnew[k]=cArr[j];
            }
            return cArrnew;
            } else {
                return null;
            }
                } else {
                    return null;
                }
        }
        static char[] removeElement(int i){
            if(cArr.length>2){
            char[] cArrnew=new char[cArr.length-2];
            for(int j=1,k=0;j<cArr.length;j++,k++){
                if(i!=j){
                    cArrnew[k]=cArr[j];
                }else{
                    k-=1;
                }
            }
            return cArrnew;}
            else{
                return null;
            }
        }
        public static void main(String[] args) {
            Scanner scn=new Scanner(System.in);
            while(true){
                temp=0;
            String s=scn.next();
            char[] arr=s.toCharArray();
            System.out.println(chackPotentialPalindrom(arr));
            }
        }
    }

Any tips to optimize this code?I could not write this in an interview as they have given a pen and paper to code.It took 3 hrs for me to write this. Can I be a developer?

MBo :

Title says "without loop" but you need to check all symbol pairs, so using recursion, as you have tried, looks reasonable. But you don't check and use results of recursive calls.

Pseudocode might look like (note we don't need to change source data or extract substring):

Edit to provide possibility to alter one char

boolean checkPotentialPalindrom(char[] cAr, start, end, altcnt){
       if (end <= start)
             return true

       if (cAr[start] != cAr[end])
            altcnt = altcnt + 1

       if (altcnt > 1) 
             return false

       return checkPotentialPalindrom(cAr, start + 1, end - 1, altcnt)
 }

and make the first call with arguments 0, len(cAr-1), 0