How to just get the method in the implement class with a generic interface in Java

Ukonn Ra :

I have a generic interface and a class implementing it:

import java.util.Arrays;

interface Interface<T> {
    void doSomething(T element);
}

class StringImpl implements Interface<String> {
    @Override
    public void doSomething(String element) {
        System.out.println("StringImpl: doSomething");
    }
}

public class Main {
    public static void main(String... args) {
        System.out.println(Arrays.toString(StringImpl.class.getDeclaredMethods()));
    }
}

And the result is

[public void com.ra.StringImpl.doSomething(java.lang.String), 
public void com.ra.StringImpl.doSomething(java.lang.Object)]

But in fact, I just want the implementing version:

public void com.ra.StringImpl.doSomething(java.lang.String)

Do you have any convient way to achieve it?

Andrew Tobilko :

Filter out bridge methods:

Method[] methods = Arrays.stream(StringImpl.class.getDeclaredMethods())
                         .filter(m -> !m.isBridge())
                         .toArray(Method[]::new);