I would like to convert my map which looks like this:
{
key="someKey1", value=Apple(id="1", color="green"),
key="someKey2", value=Apple(id="2", color="red"),
key="someKey3", value=Apple(id="3", color="green"),
key="someKey4", value=Apple(id="4", color="red"),
}
to another map which puts all apples of the same color into the same list:
{
key="red", value=list={apple1, apple3},
key="green", value=list={apple2, apple4},
}
I tried the following:
Map<String, Set<Apple>> sortedApples = appleMap.entrySet()
.stream()
.collect(Collectors.toMap(l -> l.getColour, ???));
Am I on the right track? Should I use filters for this task? Is there an easier way?
if you want to proceed with toMap
you can get the result as follows:
map.values() // get the apples
.stream() // Stream<Apple>
.collect(toMap(Apple::getColour, // group by colour
v -> new HashSet<>(singleton(v)), // have values as set of apples
(l, r) -> {l.addAll(r); return l;})); // merge colliding apples by colour
- stream over the map
values
instead ofentrySet
because we're not concerned with the map keys. Apple::getColour
is thekeyMapper
function used to extract the "thing" we wish to group by, in this case, theApple
s colour.v -> new HashSet<>(singleton(v))
is thevalueMapper
function used for the resulting map values(l, r) -> {l.addAll(r); return l;}
is the merge function used to combine twoHashSet
's when there is a key collision on theApple
's colour.- finally, the resulting map is a
Map<String, Set<Apple>>
but this is better with groupingBy
and toSet
as downstream:
map.values().stream().collect(groupingBy(Apple::getColour, toSet()));
stream over the map
values
instead ofentrySet
because we're not concerned with the map keys.groups the
Apple
's by the provided classification function i.e.Apple::getColour
and then collect the values in a Set hence thetoSet
downstream collector.finally, the resulting map is a
Map<String, Set<Apple>>
short, readable and the idiomatic approach.
You could also do it without a stream:
Map<String, Set<Apple>> res = new HashMap<>();
map.values().forEach(a -> res.computeIfAbsent(a.getColour(), e -> new HashSet<>()).add(a));
- iterate over the map
values
instead ofentrySet
because we're not concerned with the map keys. - if the specified key
a.getColour()
is not already associated with a value, attempts to compute its value using the given mapping functione -> new HashSet<>()
and enters it into the map. we then add theApple
to the resulting set. - if the specified key
a.getColour()
is already associated with a valuecomputeIfAbsent
returns the existing value associated with it and then we calladd(a)
on theHashSet
to enter theApple
into the set. - finally, the resulting map is a
Map<String, Set<Apple>>