MariaDB execute UPDATE and then DELETE if condition is true

larrybg :

I'm writing a Node JS app and need to execute UPDATE and DELETE queries in the same statement, but DELETE should be executed in another table and only if the condition equals a certain state. I'm not sure about my syntex... Here is what I have so far:

UPDATE vm_log SET user_id_fk = (SELECT user_id FROM users WHERE username = ?), vm_state = ? WHERE vm_id = ?;
SET @vmState = ?;
IF @vmState = 'PERMANENT' THEN
DELETE FROM vm_ext_tracking WHERE vm_fk = ?;
END IF

Where ? are supplied as paramaters. For example username = 'someUser', vm_state = 'ACTIVE' or PERMANENT, and vm_id some number: vm_id = 4303. The UPDATE part works fine separately, just need to add a layer of complexity with DELETE. The error message I receive:

#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'IF @vmState = 'PERMANENT' THEN
DELETE FROM vm_ext_tracking WHERE vm_fk = 4303' at line 1

Akina :

UPDATE vm_log 
SET user_id_fk = ( SELECT user_id 
                   FROM users 
                   WHERE username = ?), 
    vm_state = ? 
WHERE vm_id = ?;

SET @vmState = ?;

DELETE 
FROM vm_ext_tracking 
WHERE vm_fk = ?
  AND @vmState = 'PERMANENT';

PS. @vmState is excess, if you do not need in it in the below (not shown) code you may use

UPDATE vm_log 
SET user_id_fk = ( SELECT user_id 
                   FROM users 
                   WHERE username = ?), 
    vm_state = ? 
WHERE vm_id = ?;

DELETE 
FROM vm_ext_tracking 
WHERE ? = 'PERMANENT'
  AND vm_fk = ?;