[C/C++ puzzles] *, **, :: , &, *&, **& and function parameter passing - seven detailed explanations

foreword

Recently, pointer learning is still easy to get lost, so reorganize and learn!

Learn about it!

The reason why the C language is named "C" is to take the second letter of "BCPL" (the first letter is used to name the B language that was invented before). When the development of the C language reached its peak, a version called C with Class appeared, which was the earliest version of C++. The class keyword and class were added to the C language. At that time, there were many versions of C that hoped to be added to the C language. The concept of class; later, the C standard committee decided to give this version of C a new name. At that time, a lot of names were collected, and finally the opinion of one of them was adopted, and the ++ operator in the C language was used to reflect it. The progress of the C language, so it is called C++, and the C++ Standards Committee was established.

1. Usage of * in C/C++

  1. Simplest multiplication:
a*b;
  1. Code comments:
/**/
  1. pointer:

A pointer is an address to a variable.

Example:

int main()
{
    
    
	int a = 3;
	int *b = &a;
	cout << "a:" << a << endl;
	cout << "b:" << b << endl;
	*b = 10;
	cout << "&a:" << &a << endl;
	cout << "b:" << b << endl;
	system("pause");
}

result:

a:3
b:00EFFE28
&a:00EFFE28
b:00EFFE28
a:10

analyze:

b is a pointer to a, pointing to the address of a, both point to the same memory space (that is, a and b are connected, as long as the value of *b is modified, the value of a also changes).

2. Usage of & in C/C++

  1. bitwise operators
a&b
  1. Logical AND &&
if((a==0)&&(b==0)){
    
    }
  1. Quote & (most important)

A reference is an alias for a variable.

It can be said that the a variable is renamed to b, that is:

&b=a

Example:

//引用
int main()
{
    
    
	int a = 3;
	int &b = a;
	int c = a;
	cout << "a:" << a << endl;
	cout << "b:" << b << endl;
	cout << "c:" << c << endl;
	b = 10;
	cout << "a:" << a << endl;
	cout << "b:" << b << endl;
	cout << "c:" << c << endl;
	cout << "&a:" << &a << endl;
	cout << "&b:" << &b << endl;
	cout << "&c:" << &c << endl;
	system("pause");
}

result:

a:3
b:3
c:3
a:10
b:10
c:3
&a:0019FD74
&b:0019FD74
&c:0019FD5C

analyze:

& Quotes: For example, how many nicknames a person has, but they all refer to that person, and the same goes for quotes. If the value of b changes, it also means that the value of a has changed.

3. Function parameters

3.1 Functions pass in common parameters

//函数传入普通参数
void fun(int a,int b)
{
    
    
	int c = 0;
	c = a;
	a = b;
	b = c;
}
int main()
{
    
    
	int a = 1;
	int b = 2;
	cout << a << "," << b << endl;
	fun(a, b);//a,b交换
	cout << a << "," << b << endl;
	system("pause");
	return 0;
}

result:

1,2
1,2

analyze:

The function passed in is a formal parameter, and it will not change the address of a and b in main(), that is, it will not change the value of a and b.

3.2 Functions pass in pointer parameters

//函数传入指针参数
void fun(int *a, int *b)
{
    
    
	int c = 0;
	c = *a;
	*a = *b;
	*b = c;
}
int main()
{
    
    
	int a = 1;
	int b = 2;
	cout << a << "," << b << endl;
	fun(&a, &b);//a,b交换
	cout << a << "," << b << endl;
	system("pause");
	return 0;
}

result:

1,2
2,1

analyze:

The parameter passed to the function is a pointer, that is, an address. The exchange of a and b in the function is the exchange of the value of the address. Finally, the values ​​of a and b in main() also change.

3.3 Passing in function parameters by reference

Simple – easy to use, recommended!

//引用传入函数参数
void fun(int &a, int &b)
{
    
    
	int c = 0;
	c = a;
	a = b;
	b = c;
}
int main()
{
    
    
	int a = 1;
	int b = 2;
	cout << a << "," << b << endl;
	fun(a, b);//a,b交换
	cout << a << "," << b << endl;
	system("pause");
	return 0;
}

result:

1,2
2,1

analyze:

In essence, the a and b variables in main() are renamed, that is: a, b in the function, and the addresses of a and b in the function are the same as the addresses in main(). If the values ​​of a and b in the function change, then the values ​​of a and b in main() also change.

The essence of the citation is :The C++ internal implementation is a pointer constant.

Please move to : [C++ Core Programming] Reference (2)

4. Usage of :: in C/C++

:: refers to the scope operator, or scope qualifier.

With two colons together, this symbol has two names in C++:

  • unary scope resolution operator
  • Binary Scope Resolution Operator

When used as a unary scope resolution operator, it can be used in the following cases:

int a = 3;
int main()
{
    
    
	int a = 4;
	cout << ::a << endl; // 这时输出的是全局变量a
	cout << a << endl; // 这时输出的是局部变量a
	return 0;
}

When it is used as a binary scope discrimination operator, it is mainly used to bind the member functions of the class in the source file, such as:

a.h
class a
{
    
    
public:
	void fun1();
	int fun2();
private:
	int x;
};

a.cpp
#include "a.h"
void a::fun1()
{
    
    
.......
}
int a::fun2()
{
    
    
......
}

Binding member functions in a class:

class Building
{
    
    

public:
	Building();

public:
	string m_SittingRoom; //客厅
private:
	string m_BedRoom;//卧室
};

Building::Building()
{
    
    
	this->m_SittingRoom = "客厅";
	this->m_BedRoom = "卧室";
}

5. Usage of ** in C/C++

Simply put, it means a two-dimensional pointer (double pointer).

have to be aware of is. A single * can represent a one-dimensional array, then ** can represent a special array composed of arrays: a two-dimensional array.

This is a pointer to a pointer, such as: int * *p;p is a pointer variable that points to pointer data.

E.g:

int i=5;
int *p;
p=&i;
int **q;
*q=p;
printf("%d",**q); //输出结果是5

6. Usage of *&, **& in C/C++

Quote &, as we all know, what does the *& and **& mean respectively?

int *&p;
int **&p;

其实这两个*& 和 **&是表示引用,*&表示指针的引用,**&表示指针的指针的引用。

Example:

void foo(int*& x, int**& y) {
    
    
    // modifying x or y here will modify a or b in main
}
 
int main() {
    
    
    int val = 42;
    int *a  = &val;
    int **b = &a;
 
    foo(a, b);
    return 0;
}

Modifying x and y in the calling function will directly affect the values ​​of a and b in the main function. because they are referenced.

void pass_by_value(int* p)
{
    
    
    //Allocate memory for int and store the address in p
    p = new int;
}
 
void pass_by_reference(int*& p)
{
    
    
    p = new int;
}
 
int main()
{
    
    
    int* p1 = NULL;
    int* p2 = NULL;
 
    pass_by_value(p1); //p1 will still be NULL after this call
    pass_by_reference(p2); //p2 's value is changed to point to the newly allocate memory
 
    return 0;
}

Reference : Link Link


come on!

grateful!

effort!

Guess you like

Origin blog.csdn.net/qq_46092061/article/details/123465426