Codeforces 581A - Vasya the Hipster 题解
题目意思:
让你输入红色袜子的个数和蓝色袜子的个数,让你输出可以穿一只蓝色袜子和一只红色袜子的天数和剩余袜子能让你穿的天数。(一只袜子穿一天,真有钱¥)
题目思路:
先输出少数袜子然后让多数的袜子减少数的袜子/2在输出就行了O(∩_∩)O
#include<iostream>
#include<iomanip>
#include<set>
#include<cmath>
#include<algorithm>
#include<cstring>
#include<string>
#include<queue>
#include<stack>
#include<vector>
#include<cstdio>
using namespace std;
int main(){
int blue,red;
cin>>blue>>red;
if(blue>red){
blue=blue-red;
cout<<red<<' '<<blue/2;
}
else if(red>blue){
red=red-blue;
cout<<blue<<' '<<red/2;
}
else cout<<blue<<' '<<0;//输出red也行
return 0;
}
(・ω・) ( ̄▽ ̄)