java output every bit of any integer

Output every bit of any integer

Non-recursive way:

import java.util.*;
public class Exe{
    
    
    public static void main(String[] args){
    
    
        Scanner input = new Scanner(System.in);
        System.out.println("请输入一个整数:");
        int count = input.nextInt();
        int m,i=1,j,t,k;
        m=count;
        while(m>9){
    
      //判断n是几位数
            m=m/10;
            i++;
        }
        if(count>9)
            System.out.println(count+"是"+i+"位数");
        if(count<10){
    
       //顺序输出
            System.out.println(count+"是一位数:"+count);//个位数被10整除都为0,
        }
        else{
    
    
            for(k=i;k>0;k--){
    
    
                m=count;t=1;
                for(j=0;j<k-1;j++){
    
    
                    t*=10;
                }
                m=m/t;m=m%10;
                System.out.print(m+" ");
            }
        }
    }
}

Running result:
Insert picture description here
recursive mode:

import java.util.*;
public class Exe1{
    
    
    public static void func(int n){
    
    
        if(n>9){
    
    
            func(n/10);
        }
        System.out.println(n%10);
    }
    public static void main(String[] args){
    
    
        Scanner input = new Scanner(System.in);
        System.out.println("请输入一个整数:");
        int n = input.nextInt();
        func(n);
    }
}

operation result:
Insert picture description here

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Origin blog.csdn.net/qq_47364122/article/details/110728637