Simulation, be careful not to undercount
Answer: 8879
#include <iostream>
using namespace std;
int day[15]={
0,31,28,31,30,31,30,31,31,30,31,30,31};
void runnian(int y){
if((y%4==0&&y%100!=0)||y%400==0)
day[2]=29;
else//不能省去,不能保证上一年2月是28天
day[2]=28;
}
int main()
{
int ans=0;
// runnian(2200);
// cout<<day[2];
int y=2000,m=1,d=1,w=6;
while(!(y==2020&&m==10&&d==1)){
//2020.10.1截至
//今天
if(w==1 || d==1)
ans++;
ans++;
//明天
d++;
w=(w+1)%7;
if(d>day[m]){
d=1;
m++;
if(m>12){
y++;
m=1;
}
}
runnian(y);
}
cout<<ans+2;//2020.10.1后没算
return 0;
}