Player guessing game (v2.0)

Subject requirements:

1. The system randomly generates an integer between 0 and 99 (including 0 and 99);

2. The player enters an integer, and the system prompts the relationship between the value and the random number according to the value entered by the player for the player's reference;

3. If the player fails to guess correctly ten times in a row, he will decide whether to enter the next round of guessing game according to his choice.

[Summary of running problems] The random number generated by the rand() function is a "pseudo-random number", and the random number (group) generated every time the program is run is the same: this is where the v2.1 version should be optimized.

#include<stdio.h>
#include<stdlib.h>
void f()//用户抽奖流程
{
    int magic;
    int guess;//记录用户输入的数
    char i;//循环控制变量
    char flag='Y';
    printf("猜数游戏开始!\n");
    while(flag=='Y')
    {
        i=0;
        magic=rand()%100;//生成一个介于0~99之间的整数(包括0和99)
        printf("当前次数:\n");
        while(i<10)
        {
            printf("%d.  请输入一个介于0~99之间的整数: ", i+1);
            scanf("%d", &guess);
            if(guess==magic)
            {
                printf("猜对了!\n");
                break;
            }
            else if(guess<magic)
            {
                printf("猜小了.\n");
            }
            else
            {
                printf("猜大了.\n");
            }
            i++;
        }
        printf("请选择是否进入下一轮猜数游戏(Y/N): ");
        scanf(" %c", &flag);
    }
    //
    printf("欢迎您下次再来!\n");
    //
    return ;
}
int main()
{
    f();
    return 0;
}